Appending variable in PHP causes Syntax Error

Question

What is wrong with this php code?

$sql = mysql_query("select * from news where isActive = 1 and partnerid_fk = '$partnerid'");
$news = "";
while($row = mysql_fetch_assoc($sql)) {
    news .= "<li class='news-item'><a href='#'>" . $row['news'] . "</a></li>";
}

Error on the news append line:

Syntax error.

no dollar sign in variable news in the loop

Wilq
– Wilq

2013-01-20 15:45:18 +00:00
Commented Jan 20, 2013 at 15:45 — Wilq
– Wilq, Commented Jan 20, 2013 at 15:45
you forgot a $ in news

Majid Laissi
– Majid Laissi

2013-01-20 15:45:43 +00:00
Commented Jan 20, 2013 at 15:45 — Majid Laissi
– Majid Laissi, Commented Jan 20, 2013 at 15:45

John Conde · Accepted Answer · 2013-01-20 15:44:54Z

4

You forgot your dollar sign:

news .=

should be

$news .=

answered Jan 20, 2013 at 15:44

John Conde

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1 Comment

nimrod Over a year ago

I completely focused on the right part of the line :) thank you

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