Display Javascript variable into PHP variable

Question

In my form action there's a url: www.url.com/?quantity=$quantity

And in the form there's a select box where customers choose the quantity.

<form method="post" name="jform" action="www.url.com/?quantity=$quantity">
<select class="font_12" id="quantity" name="quantity">
    <option value="10">10 PCs</option>
    <option value="25">25 PCs</option>
    <option value="50">50 PCs</option>
    <option value="99">99 PCs</option>
</select>

I am trying to get the value in the select box using ajax, and then display into the action form url. I did a alert and it works, I am getting the value of the select box. But I don't know how to put this vaue into the PHP varaible $quantity?

Here's my Ajax code:

$('#quantity').on('change', function() {
var val = $(this).val();
if(val != '') {
    $.get('index.php', {'quantity' : val}, function(resp) {
        alert(val);
    });
}
});

Actually I want it to change the php variable right away when the quantity in the select box change before submitting the form.

Any help?

When do you want PHP to be able to access the quantity variable? — Explosion Pills
– Explosion Pills, Commented Jan 30, 2013 at 18:45
I try $_GET, but when the page load I am getting a undefined error — Ya Fa Su
– Ya Fa Su, Commented Jan 30, 2013 at 18:49

Marcus Recck · Accepted Answer · 2013-01-30 19:04:01Z

2

Use $_GET

If your URL is ?quantity=### then just use $_GET['quantity'] in your PHP code.

To change the action attribute on the form when you change the quantity you can just put the following inside your onchange event:

$('form[name="jform"]').attr('action','http://url.com/?quantity=' + val);

edited Jan 30, 2013 at 19:04

answered Jan 30, 2013 at 18:46

Marcus Recck

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9 Comments

lud Over a year ago

and be careful to properly control your users' input

Ya Fa Su Over a year ago

not working, the url is in the form action. I want it to change the quantity of the form action url when a value in the select value is changed.

Marcus Recck Over a year ago

Well then since you're using jQuery you can just say $('form[name="jform"]').attr('action','http://url.com/?quantity=' + val);

Ya Fa Su Over a year ago

Oh thank you so much, but how about if I am using a php function in the action like:<form method="post" name="jform" action="<?php echo url($quantity) ?>">

Marcus Recck Over a year ago

Then you can use action="http://url.com/?quantity=<?php echo (int)$_GET['quantity']; ?>"

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