javascript capture and display php variable

Question

I have standard text links which all say "Full View". When clicked these links send out php in this form: http://mysite.com/fullview.php?myimage=30

Basically there's thumbnailed images and text links that say full view. I'd like for fullview.php to capture the myimage variable, and display it as a full sized image. Meaning, a blank page (fullview.php) displaying the image. Sounds likes javascript to me.

How do you put the javascript into fullview.php to capture the variable and display it as a full sized image?

Thanks for any help, Darrell

i100 · Accepted Answer · 2011-08-27 19:00:28Z

1

php is server side script javascript is client side script

so displaying a web page to a user first is executed php and result is send to client. After he receive it then javascript is executed

HTH

Ivo Stoykov

answered Aug 27, 2011 at 19:00

i100

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3 Comments

Darrell Over a year ago

Thanks, that's what I'm trying to do, but how.

i100 Over a year ago

from php you have to 'echo' your javascript i.e. echo "var test = 'test string';"; javascript's variable you could pass to php either via query string (and access them with $_GET) or via html form ($_POST). Alternatively you could use ajax. No other ways

Darrell Over a year ago

Got rid of the text links, and linked off of the thumbnails to open full image in blank window. Thanks for your help.

Treffynnon · Accepted Answer · 2011-08-27 19:09:14Z

1

You just need to read the query parameters. In fullview.php you can use

$myimage = $_GET['myimage']; to capture this variable. And then can use it accordingly.

edited Aug 27, 2011 at 19:09

Treffynnon

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answered Aug 27, 2011 at 18:59

sushil bharwani

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5 Comments

Darrell Over a year ago

How do you use it? Inside an image tag? How do you get this to display the picture in fullview.php?

sushil bharwani Over a year ago

what do you want to do with the value 30?

Darrell Over a year ago

The value 30 could be any number. The value represents an image. Example: image number 46. I want to use the current variable to display the image on fullview.php. Fullview.php is basically a blank page.

Darrell Over a year ago

I tried 20 variations of this with no success. Any javascript solutions you can think of? As the other person who answered said, "php is server side script javascript is client side script"

Darrell Over a year ago

any ideas about the javascript solution?

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