Java : Simple Loop

Question

Here is a simple version without any loops. How can I make it loop like "Wrong password. Try again." until user puts the right password instead stopping the program (or give them 3 chances before it stops)?

    import java.util.Scanner;
public class helloworld2
{
    public static void main(String[] arg)
    {
        Scanner q = new Scanner(System.in);
        long Pass;
        boolean auth = true;

        System.out.println("Enter Password :");
        Pass = q.nextLong();

        if ( Pass != 1234 )
           {
           System.out.println("Wrong Password!");
           auth = false;
           }
        else
           {
           System.out.println("Password Confirmed.");
           auth = true;
           }

        if (auth) {
            ////blablabla
            }

        else
          {
            return;
          }                 
    }
}

variable names musn't be capitalized (Pass) That's for class names. — Adrián
– Adrián, Commented Feb 4, 2013 at 17:54
Bad idea to do things in the main method, its static definition makes it impossible to access non-static fields, instead instantiate a new helloworld2 object and define your behavior in the constructor. — Jimmt
– Jimmt, Commented Feb 4, 2013 at 18:28

Simulant · Accepted Answer · 2013-02-04 17:56:21Z

3

public class helloworld2
{
    public static void main(String[] arg)
    {
        Scanner q = new Scanner(System.in);
        long Pass;
        boolean auth = true;
        boolean rightPassword = false;
        while(!rightPassword){//repeat until passwort is correct
          System.out.println("Enter Password :");
          Pass = q.nextLong();

          if ( Pass != 1234 )
          {
            System.out.println("Wrong Password!");
            auth = false;
          }
          else
          {
            rightPassword = true;//let the loop finish
            System.out.println("Password Confirmed.");
            auth = true;
          }
        }
        // Here do what you want to do
        //because here the user has entered a right password                 
    }
}

edited Feb 4, 2013 at 17:56

Simulant

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answered Feb 4, 2013 at 17:50

William Kinaan

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