What is the usual way in MATLAB to read an integer into an array, digit by digit?
I'm trying to split a four digit integer, 1234 into an array [1 2 3 4].
4 Answers
Here is a very easy way to do it for a single integer
s = num2str(1234)
for t=length(s):-1:1
result(t) = str2num(s(t));
end
The most compact way however, would be:
'1234'-'0'
answered Feb 15, 2013 at 13:19
Dennis Jaheruddin
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4 Comments
Dennis Jaheruddin
@Dan This uses the fact that character codes are ordered in the same way as numbers. So the character code of
'1' is exactly 1 higher than the character code of '0'. Try '0' + 0 to find out what the codes actually are.
Dan
right I see, excellent solution. Why even bother to post the loop?
Dennis Jaheruddin
@Dan As the loop can be generalized more easily. With this method it is not so hard to produce
[12 23 34 41] for example.
Carl Witthoft
Note: for a matrix of numbers,
num2str(matrix) - '0' will sorta work, but will return a bunch of columns of -16 due to the spaces in the character matrix produced with num2strOr try this
result = str2num(num2str(1234)')'
answered Feb 15, 2013 at 13:17
High Performance Mark
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1 Comment
Carl Witthoft
This works, but sadly not for a matrix of values (as opposed to the vector in your example).
Here is an elegant and efficient solution using a recursive function:
function d = int2dig(n)
if n >= 10
d = [int2dig(floor(n/10)),mod(n,10)];
else
d = n;
end
1234a numeric value (like the body of the question suggests) or a string (char, like the title suggests)?