I have an cell-array of dimensions 1x6 like this:
A = {'25_2.mat','25_3.mat','25_4.mat','25_5.mat','25_6.mat','25_7.mat'};
I want to read for example from the A{1} , the number after the '_' i.e 2 for my example
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3 Answers
Using cellfun, strfind and str2double
out = cellfun(@(x) str2double(x(strfind(x,'_')+1:strfind(x,'.')-1)),A)
How does it work?
This code simply finds the index of character one number after the occurrence of
'_'. Lets call it asstart_index. Then finds the character one number lesser than the index of occurrence of'.'character. Lets call it asend_index. Then retrieves all the characters betweenstart_indexandend_index. Finally converts those characters to numbers usingstr2double.
Sample Input:
A = {'2545_23.mat','2_3.mat','250_4.mat','25_51.mat','25_6.mat','25_7.mat'};
Output:
>> out
out =
23 3 4 51 6 7
4 Comments
Devel
that's fine for 1 to 9 once I have for exemple 25_10.mat | 25_11.mat ... it returns: 1 1 but I want: 10 11 so finally I want to have with the same function : 2 3 4 5 6 7 8 9 10 11 etc..
Santhan Salai
@Devel Edited for that. Can you check it out?
Devel
just one more question please, if i want just only one number example A(1) I mean i want only the "2" how to deal?
Santhan Salai
@Devel
out(1) should do.. Add it after the code. (you can do it for any cell number)You can access the contents of the cell by using the curly braces{...}. Once you have access to the contents, you can use indexes to access the elements of the string as you would do with a normal array. For example:
test = {'25_2.mat', '25_3.mat', '25_4.mat', '25_5.mat', '25_6.mat', '25_7.mat'}
character = test{1}(4);
If your string length is variable, you can use strfind to find the index of the character you want.
Comments
Assuming the numbers are non-negative integers after the _ sign: use a regular expression with lookbehind, and then convert from string to number:
numbers = cellfun(@(x) str2num(x{1}), regexp(A, '(?<=\_)\d+', 'match'));
