I want to get the directory where the file resides. For example the full path is:
fullpath = "/absolute/path/to/file"
# something like:
os.getdir(fullpath) # if this existed and behaved like I wanted, it would return "/absolute/path/to"
I could do it like this:
dir = '/'.join(fullpath.split('/')[:-1])
But the example above relies on specific directory separator and is not really pretty. Is there a better way?
You are looking for this:
>>> import os.path
>>> fullpath = '/absolute/path/to/file'
>>> os.path.dirname(fullpath)
'/absolute/path/to'
Related functions:
>>> os.path.basename(fullpath)
'file'
>>> os.path.split(fullpath)
('/absolute/path/to','file')
import os.path instead of simply import os?
os.path won't allow me to import os.anything_else (i.e. I need to import os). Found myself wrong when I tried it.