ArrayIndexOutOfBounds When Splitting String

Question

I am trying to extract information from a file that is formatted as follows:

1
[email protected]|password|false

However, I seem to be getting ArrayIndexOutOfBounds errors when running the following code and I am unable to determine the reason for this as I believe that my splitting should be functioning correctly. The error is obtained on the line beginning with "users".

        sc = new Scanner (System.in);
        BufferedReader in = new BufferedReader (new FileReader (USAVE));
        int repeats = Integer.parseInt(in.readLine());
        for (int c = 0; c < repeats; c++){
            String info = in.readLine();
            System.out.println (info);
            String[] extracted = info.split("\\|");
            users.addUser(extracted[0], decryptPassword(extracted[1]));
        }
        in.close();

What could be the problem?

EDIT: I have changed "|" to "\|" but the problem persists.

EDIT2: StackTrace

Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 1
at OnlineCommunications.userFromFile(OnlineCommunications.java:165)
at OnlineCommunications.logIn(OnlineCommunications.java:36)
at OnlineCommunications.emailOption(OnlineCommunications.java:593)
at OnlineCommunications.main(OnlineCommunications.java:683)

The method I have posted above is the one named userFromFile.

PermGenError · Accepted Answer · 2013-02-28 23:40:17Z

6

String#split(regex) expects regex as a parameter and | is a meta character(special character) in regex world. In order to treat a meta charcter as a normal character you should escape it with backslash(\|)

String[] extracted = info.split("\\|");

or just include it inside a charcter class

String[] extracted = info.split("[|]");

Below are the meta characters in regex:

<([{\^-=$!|]})?*+.>

answered Feb 28, 2013 at 23:40

PermGenError

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5 Comments

osm Over a year ago

Thank you for your answer but it seems that I'm still getting the error. :( I had previously tried using "," to separate the values as well.

PermGenError Over a year ago

@mCode if i apply the split to [email protected]|password|false i get emailadd at index 0 password at index 1 and false at index 2. are you sure this is thesource of your exception. can you update the post with stacktrace please.

osm Over a year ago

@PremGenError I have updated with a stacktrace (I am not sure what a stacktrace is so please let me know if that is not it).

PermGenError Over a year ago

@mCode whats on line 165 ?? and are you sure info prints out [email protected]|password|false??

osm Over a year ago

@PremGenError Line 165 contains users.addUser(extracted[0], decryptPassword(extracted[1]));. I am assuming that info should be putting out the mentioned String because the in.readLine() should be telling it to behave as such. Perhaps it is an error of the BufferedReader? I should add that System.out.println(info); does not print anything before the error.

Eng.Fouad · Accepted Answer · 2013-02-28 23:40:59Z

2

String.split(String regex) takes a regular expression as an argument, use:

String[] extracted = info.split("\\|");

answered Feb 28, 2013 at 23:40

Eng.Fouad

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1 Comment

osm Over a year ago

Thank you for your answer but it seems that I'm still getting the error. :( I had previously tried using "," to separate the values as well.

Community · Accepted Answer · 2017-05-23 12:28:23Z

1

similar post. Tokenizing Error: java.util.regex.PatternSyntaxException, dangling metacharacter '*' You have to use like this :

String[] extracted = info.split("\\|");

edited May 23, 2017 at 12:28

CommunityBot

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answered Feb 28, 2013 at 23:42

Ahmet Karakaya

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1 Comment

osm Over a year ago

Thank you for your answer but it seems that I'm still getting the error. :( I had previously tried using "," to separate the values as well.

CincinnatiKid · Accepted Answer · 2013-03-01 00:57:43Z

0

Actually there is nothing wrong with how you are parsing the string. The error lies elsewhere. I would add System.out.println (repeats) just before you enter the loop to make sure you are iterating the correct number of times. To debug even further, I would print the contents of extracted (Arrays.toString(extracted)) before the line invoking user.addUsers. If all that looks good, then the problem lies in the user.addUsers invocation.

edited Mar 1, 2013 at 0:57

answered Mar 1, 2013 at 0:33

CincinnatiKid

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1 Comment

CincinnatiKid Over a year ago

I would look closer at what is going on in the user.addUser line. You didn't post the code, so I can't help you there. But, if you take that line out and just println extracted[0] and extracted[1] you don't get ANY errors.

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