Getting an ArrayIndexOutOfboundsException when splitting a string into an array and then looping over it

Question

I am trying to send the result of a split() function into an array of strings, but I am getting an exception as follows:

java.lang.ArrayIndexOutOfBoundsException: somenumber

I am using the following code, but it returns that exception:

String[] temp;
temp = result.split(" ");

Any suggestions? I want to send the result of the string split() function into an array of strings, and then print the values in a for loop.

I am getting an out of bounds exception in for loop, I use:

for (int i=0;i<=temp.length;i++)
{
    out.println(temp[i]);
}

The code you've provided wouldn't even compile, as you can't assign a string array to a String variable. Please post a short but complete program which does compile. — Jon Skeet
– Jon Skeet, Commented Mar 30, 2012 at 14:49
@King Aslan, see my edited answer: it should explain fairly well on why the new error is happening. — user1181445
– user1181445, Commented Mar 30, 2012 at 15:05

score 3 · Accepted Answer · 2012-03-30 15:04:45Z

3

String temp;
String[] split = result.split(" ");
temp = split[temp.length - 1];

You were declaring a String array as a single string, then declaring a new String in the wrong way.

EDIT: saw you updated your post:

You have to use less then for the condition in the for loop. If an array has 5 elements, the last element will be 4, not 5. The correct code is:

for(int i = 0; i < temp.length; i++){
  System.out.println(temp[i]);
}

You can even do:

for(String cur : temp){
  System.out.println(cur);
}

edited Mar 30, 2012 at 15:04

answered Mar 30, 2012 at 14:49

user1181445

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1 Comment

user1181445 Over a year ago

No problem. If you want, feel free to do some challenges on CodingBat. They are good for these type of methods and will help explain. I am currently making a similar program but offline.

talnicolas · Accepted Answer · 2012-03-30 14:49:35Z

0

The split() method (doc) returns an Array of String, so your temp variable should be a String[].

answered Mar 30, 2012 at 14:49

talnicolas

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Comments

Guillaume Polet · Accepted Answer · 2012-03-30 14:49:52Z

0

Your code can't work like that. split returns String[].

String someString = "hello world";
String[] split = someString.split(" ");
String hello = split[0];
String world = split[1];
String lastWord = split[split.length-1];

answered Mar 30, 2012 at 14:49

Guillaume Polet

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gpeche · Accepted Answer · 2012-03-30 14:49:57Z

0

This?

String[] parts = original.split(" ");

answered Mar 30, 2012 at 14:49

gpeche

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Andrés Oviedo · Accepted Answer · 2012-03-30 15:02:16Z

0

If you want to store the result (length of the array?) in the same array that generated the split() function, then you can't. You would have to create another array of bigger length:

String result = "Hello World";
String[] temp;
temp = result.split(" ");
String[] temp2 = Arrays.copyOf(temp, temp.length + 1);
temp2[temp.length] = String.valueOf(temp.length);
System.out.println(Arrays.toString(temp2));

The output is: [Hello, World, 2]

answered Mar 30, 2012 at 15:02

Andrés Oviedo

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