I am trying to convert a BigInteger or a String variable containing no.s into a BigInteger Array. How can i do this. please reply. for eg.
BigInteger = 278490638904984
BigInteger Array = [2,7,8,4,9,0,6,3,8,9,0,4,9,8,4]
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4 Answers
public static void main(String[] args) {
String s = "278490638904984";
BigInteger[] big = new BigInteger[s.length()];
for (int i = 0; i < s.length(); i++) {
big[i] = new BigInteger(String.valueOf(s.charAt(i)));
}
System.out.println(Arrays.toString(big));
}
Output:
[2, 7, 8, 4, 9, 0, 6, 3, 8, 9, 0, 4, 9, 8, 4]
Comments
You should be able to do this:
BigInteger bi = new BigInteger(myString);
You then will have to assign that to a position in an array of BigIntegers.
Note, if your string cannot be converted, it will throw a NumberFormatException.
Comments
For which purpose? It's a little bit strange...
BigInteger bi = new BigInteger( "278490638904984" );
String s = bi.toString();
int len = s.length();
BigInteger[] digits = new BigInteger[len];
for( int i = 0; i < len; ++i ) {
digits[i] = BigInteger.valueOf( s.charAt(i)-'0' );
}
1 Comment
Oleksii Morenets
charAt(i) - '0' is equal to Character.toNumericValue()
Try to convert BigInteger value toString(), then get length of the String like str.length() and create an array of desired size.
After this you can fill the array with values:
array[i] = new BigInteger(str.substring(i, i+1));
It's not brilliant solution, but should do the job.
