conversion of array of decimal string to biginteger

Question

How can I convert array of string containing decimal numbers to big integer?

eg:

String s={"1","2","30","1234567846678943"};

My current code:

Scanner in = new Scanner(System.in);
int n = in.nextInt();
String s[]= new String[n];

for(int i=0; i < n; i++){
 s[i] = in.next();
}

BigInteger[] b = new BigInteger[n];
for (int i = 0; i < n; i++) {
  b[i] = new BigInteger(String s(i));
}

You don't really need to populate an array of Strings and convert it later to an array of BigInteger. You can do it with just one for loop. BigInteger[] b = new BigInteger[n]; for(int i=0; i < n; i++){ b[i] = new BigInteger(in.next()); } — Anton Balaniuc
– Anton Balaniuc, Commented Feb 21, 2017 at 11:33

GhostCat · Accepted Answer · 2017-02-21 11:24:04Z

1

Here:

b[i] = new BigInteger(String s(i));

should be:

b[i] = new BigInteger(s[i]);

In other words: you got half of your syntax correct; but then seem to forget how to read an already defined array slot:

you use [index] square brackets ( "( )" are only used for method invocations)
No need to specify that "String" type within that expression

answered Feb 21, 2017 at 11:24

GhostCat

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Raman Sahasi · Accepted Answer · 2017-02-21 12:52:40Z

0

Just use new BigInteger(s[i]); instead of new BigInteger(String s(i));

FYI, you don't really have to use a separate String array to store initial values. You can directly store them in BigInteger array. Somewhat like this:

Scanner in = new Scanner(System.in);
int n = in.nextInt();

BigInteger[] b = new BigInteger[n];

for(int i=0; i < n; i++){
    b[i] = new BigInteger(in.next());
}

answered Feb 21, 2017 at 12:52

Raman Sahasi

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