Not able to pass a string value in javascript function

Question

for(int i = 0; i < ob.length; i++) {
  logger.logDebug(this.getClass(),"ob value check- "+ob[i].toString());
  String val=ob[i].toString();
  strXML1.append("<graph caption='City Wise Total Properties' xAxisName='City' yAxisName='Count' decimalPrecision='0' formatNumberScale='0'>")
         .append("<set name='")
         .append(ob[i].toString())
         .append("'  value='" + ob1[i].toString())
         .append( "'color='A186BE' link='javascript:drillDownReport1(2,"+val+")' />")
         .append("</graph>");
  }

I am not getting the value of val using the following JavaScript function:

function drillDownReport1(reportnumber,val) {
    alert("val"+val);
}

Any help appreciated!

please help for what? what you need to do and what is the question here? — Chamika Sandamal
– Chamika Sandamal, Commented Apr 2, 2013 at 11:17
You are asking or telling something? Completely unable to get you :( You can't just pick a portion of Code and put in a question like this. Indeed, you need to elaborate it a bit :) — Arslan Ali
– Arslan Ali, Commented Apr 2, 2013 at 11:20
@SubirKumarSao I am not getting any alert...It throws error value of val is undefined.......... — Mahesh Pachpande
– Mahesh Pachpande, Commented Apr 2, 2013 at 11:22
@ChamikaSandamal I need to get value of val in javascript function..But not able to get the value of val.Ob[i].tostring refers to cityname.... — Mahesh Pachpande
– Mahesh Pachpande, Commented Apr 2, 2013 at 11:25

Xavier Delamotte · Accepted Answer · 2013-04-02 11:20:28Z

2

It's because the javascript generated is, if val = "toto"

javascript:drillDownReport1(2,toto)' />")

and not

javascript:drillDownReport1(2,"toto")' />")

So you need to escape with quote your string. Like that:

.append( "'color='A186BE' link='javascript:drillDownReport1(2,\""+val+"')' />")

answered Apr 2, 2013 at 11:20

Xavier Delamotte

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1 Comment

Mahesh Pachpande Over a year ago

I have used this already...By using above way I am not able to view the fusionchart graph to whom i want to pass above stringXMl

Kaloyan · Accepted Answer · 2013-04-02 11:19:10Z

1

Use

var val=ob[i].toString();

instead of

String val=ob[i].toString();

?

Cause, you know, this is JavaScript.

answered Apr 2, 2013 at 11:19

Kaloyan

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1 Comment

Xavier Delamotte Over a year ago

This is JSP generating javascript.

vdua · Accepted Answer · 2013-04-02 11:19:28Z

0

Your problem is the way you are putting the value of val in your function

Since val is a string, you need to put that in quotes.

strXML1.append("<graph caption='City Wise Total Properties' xAxisName='City' yAxisName='Count' decimalPrecision='0' formatNumberScale='0'>")
        .append("<set name='")
        .append(ob[i].toString())
        .append("'  value='" + ob1[i].toString())
        .append( "'color='A186BE' link='javascript:drillDownReport1(2,\""+val+"\")' />")
        .append("</graph>");

answered Apr 2, 2013 at 11:19

vdua

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