I have a string that I'm using .split(' ') on to split up the string into an array of words. Can I use a similar method to split the string into an array of 2 words instead?
Returns an array where each element is one word:
words = string.split(' ')
I'm looking to return an array where each element is 2 words instead.
str = 'one two three four five six seven'
str.split.each_slice(2).map{|a|a.join ' '}
=> ["one two", "three four", "five six", "seven"]
This also handles the case of an odd number of words.
str.split.each_slice(2).map(&:join) but I can't get the ' ' argument on the join.
You can do
string= 'one1! two2@ three3# four4$ five5% six6^ sev'
string.scan(/\S+ ?\S*/)
# => ["one1! two2@", "three3# four4$", "five5% six6^", "sev"]
\s*, then it will also preserve the original whitespace between the words.
"one1!\t two2@", this would retain the tab and extra spaces (SO is only displaying one space in the example, but pretend there were many)Something like this should work:
string.scan(/\w+ \w+/)
str = 'one1! two2@ three3# four4$ five5% six6^' outputs []. I don't know if the words are all alphabeticstring.scan(/\S+ \S+/) would be better./\S+\s+\S+/ because you don't necessarily know that it's one space between words.Ruby's scan is useful for this:
'a b c'.scan(/\w+(?:\s+\w+)?/)
=> ["a b", "c"]
'a b c d e f g'.scan(/\w+(?:\s+\w+)?/)
=> ["a b", "c d", "e f", "g"]
This is all I had to do:
def first_word
chat = "I love Ruby"
chat = chat.split(" ")
chat[0]
end
