How to split string into an array

Question

Here is my sample string with values.

Sample String:-

str = "2014-09-04 21:12:05" "5469687123030383463" "192.168.1.2" "4" "7879" "0" "43" "http://www.google.com" "Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/35.0.1916.153 Safari/537.36" "404" "123" "F" "21549" "50" "0" "-" "-" "Test1":"T" "Test2":"T" "Test3":"F" "Test4":"T" "Test5":"F" "Test6":"T" "Test7":"F"

If i split using space:-

Use str.split(' ')

Result is:-

["\"2014-09-04", "21:12:05\"", "\"5469687123030383463\"", "\"192.168.1.2\"", "\"4\"", "\"7879\"", "\"0\"", "\"43\"", "\"http://www.google.com\"", "\"Mozilla/5.0", "(X11;", "Linux", "x86_64)", "AppleWebKit/537.36", "(KHTML,", "like", "Gecko)", "Chrome/35.0.1916.153", "Safari/537.36\"", "\"404\"", "\"123\"", "\"F\"", "\"21549\"", "\"50\"", "\"0\"", "\"-\"", "\"-\"", "\"Test1\":\"T\"", "\"Test2\":\"T\"", "\"Test3\":\"F\"", "\"Test4\":\"T\"", "\"Test5\":\"F\"", "\"Test6\":\"T\"", "\"Test7\":\"F\""]

But i need like below:-

Expected result:-

["\"2014-09-04 21:12:05\"", "\"5469687123030383463\"", "\"192.168.1.2\"", "\"4\"", "\"7879\"", "\"0\"", "\"43\"", "\"http://www.google.com\"", "\"Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/35.0.1916.153 Safari/537.36\"", "\"404\"", "\"123\"", "\"F\"", "\"21549\"", "\"50\"", "\"0\"", "\"-\"", "\"-\"", "\"Test1\":\"T\"", "\"Test2\":\"T\"", "\"Test3\":\"F\"", "\"Test4\":\"T\"", "\"Test5\":\"F\"", "\"Test6\":\"T\"", "\"Test7\":\"F\""]

How can i do in ruby to achieve the expected result.

How do you do it, as a human? Write down the rules, then transform them to code. — Sergio Tulentsev
– Sergio Tulentsev, Commented Sep 8, 2014 at 8:01

Stefan · Accepted Answer · 2014-09-08 08:05:42Z

2

Assuming your string is:

str = '"2014-09-04 21:12:05" "5469687123030383463" "192.168.1.2" "4" "7879" "0" "43" "http://www.google.com" "Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/35.0.1916.153 Safari/537.36" "404" "123" "F" "21549" "50" "0" "-" "-" "Test1":"T" "Test2":"T" "Test3":"F" "Test4":"T" "Test5":"F" "Test6":"T" "Test7":"F"'

You can use a regular expression with a positive lookahead / lookbehind assertion to match a space that is surrounded by quotes (without capturing the quotes):

str.split(/(?<=") (?=")/)
#=> ["\"2014-09-04 21:12:05\"",
#    "\"5469687123030383463\"",
#    "\"192.168.1.2\"",
#    "\"4\"",
#    "\"7879\"",
#    "\"0\"",
#    "\"43\"",
#    "\"http://www.google.com\"",
#    "\"Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/35.0.1916.153 Safari/537.36\"",
#    "\"404\"",
#    "\"123\"",
#    "\"F\"",
#    "\"21549\"",
#    "\"50\"",
#    "\"0\"",
#    "\"-\"",
#    "\"-\"",
#    "\"Test1\":\"T\"",
#    "\"Test2\":\"T\"",
#    "\"Test3\":\"F\"",
#    "\"Test4\":\"T\"",
#    "\"Test5\":\"F\"",
#    "\"Test6\":\"T\"",
#    "\"Test7\":\"F\""]

answered Sep 8, 2014 at 8:05

Stefan

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4 Comments

aelor Over a year ago

owww I didnt notice that the strings were in double quotes ... lol

Galet Over a year ago

@stefan if my string like this , then how i split into array of values.str = '"2014-09-04 21:12:05" 5469687123030383463 192.168.1.2 4 7879 0 43 "www.test.com/" "Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/35.0.1916.153 Safari/537.36" 404 123 F 21549 50 0 - Test1

Stefan Over a year ago

@karan that's a different task, please ask a separate question.

Galet Over a year ago

@Stefan I created ticket here stackoverflow.com/questions/25720969/…

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