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Does anyone know the syntax for this? I have a PHP file that uses argv to turn a parameter into a variable.

If I use:

php /path/to/local/phpfile/myphpfile.php variable

that works perfectly, but to a remote PHP file:

php http://remotehost/myphpfile.php variable

I get back:

"could not open input file: http://remotehost/myphpfile.php"

Fine, so I try with curl:

curl --data "variable" http://remotehost/myphpfile.php

But the variable does not get passed. Is it possible to pass shell script variables to a remote PHP file? Many thanks in advance.

1 Answer 1

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It's HTTP. use GET method, Luke

curl http://remotehost/myphpfile.php?data=variable
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