JS Variable in jQuery ajax data

Question

jQuery:

function myajax(var){
  $.ajax({
    url : 'ajax.php',
    type : 'POST',
    dataType : 'html',
    data: {
      if(undefined != var){ variable : var, }
      content : $("#myinput").val()
  }
}

However, when calling the above function, the console shows Unexpected token ( for the line with the if. How can I do this successfully? Thanks!

epascarello · Accepted Answer · 2013-05-16 17:27:45Z

2

You have an if statement inside of an object! You can not do that.

Move the logic outside of the object.

function myajax(var) {

    var data = {
        content: $("#myinput").val()
    };
    if (undefined !== var) {
        data.variable = var;
    }
    $.ajax({
        url: 'ajax.php',
        type: 'POST',
        dataType: 'html',
        data: data
    });

}

answered May 16, 2013 at 17:27

epascarello

208k20 gold badges206 silver badges246 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Vamsi Abhishek · Accepted Answer · 2013-05-16 17:42:02Z

-1

You can actually do the validation in "beforeSend"

function myajax(var){
  var requestData;
  $.ajax({
    url : 'ajax.php',
    type : 'POST',
    dataType : 'html',
    data: requestData,
    beforeSend : function(xhr){

      requestData = $("#myinput").val();
  }
}

Something like this might solve your problem

edited May 16, 2013 at 17:42

answered May 16, 2013 at 17:32

Vamsi Abhishek

1371 silver badge12 bronze badges

1 Comment

epascarello Over a year ago

what is variable : var, -1

Collectives™ on Stack Overflow

JS Variable in jQuery ajax data

2 Answers 2

Comments

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related