accessing variables in jquery ajax

Question

    var form_data = {
        username: $("#username").val(),
        password: $("#password").val(),
        is_ajax: 1
    };

    $.ajax({
        type: "POST",
        url: action,
        data: form_data,
        success: function(response) {
            if (response==username) {

I want to access username variable that i have declared in form_data variable. How can i? i am using $("#username").val() but i want to access the variable.

the solution is not worthy of an answer really. an answer could be an essay of how to access object properties in javascript or similar — Esailija
– Esailija, Commented Nov 13, 2011 at 17:38

rafael.js · Accepted Answer · 2011-11-13 17:36:05Z

2

var form_data = {
        username: $("#username").val(),
        password: $("#password").val(),
        is_ajax: 1
    };

    $.ajax({
        type: "POST",
        url: action,
        data: form_data,
        success: function(response) {
            if (response==form_data.username) {

answered Nov 13, 2011 at 17:36

rafael.js

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4 Comments

Kae Verens Over a year ago

this appears to be simply a copy/paste of the jQuery from the OP

Martin. Over a year ago

@KaeVerens: look at the last line

Greg Pettit Over a year ago

It's worth mentioning to the OP that this comparison will only work if "response" (what the server returns) is only the username as a string. You might want to structure your response to accomodate future information as well, even if the username is all you care about at this moment.

rafael.js Over a year ago

Agree with @GregPettit . When the dataType of the ajax request is text, I usually trim the response. like this: if( $.trim(response)==form_data.username) Because response often comes with blank spaces at the beginning and at the end of it.

Martin. · Accepted Answer · 2011-11-13 17:36:35Z

1

form_data.username is the variable you want

if (response == form_data.username) {

so in result, it will all look like

var form_data = {
    username: $("#username").val(),
    password: $("#password").val(),
    is_ajax: 1
};

$.ajax({
    type: "POST",
    url: action,
    data: form_data,
    success: function(response) {
        if (response == form_data.username) {

answered Nov 13, 2011 at 17:36

Martin.

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