I have a string of that displays like this:
1235, 3, 1343, 5, 1234, 1
I need to replace every second comma with a semicolon
i.e.
1235, 3; 1343, 5; 1234, 1
The string length will always be different but will follow the same pattern as the above i.e. digits comma space digits comma space, etc.
How can I do this with PHP? Is it possible?
Thanks.
Preg_replace() solution
$str = '1235, 3, 1343, 5, 1234, 1';
$str = preg_replace('/(.+?),(.+?),/', '$1,$2;', $str);
echo $str;
Output:
1235, 3; 1343, 5; 1234, 1
Try this :
$str = '1235, 3, 1343, 5, 1234, 1';
$res_str = array_chunk(explode(",",$str),2);
foreach( $res_str as &$val){
$val = implode(",",$val);
}
echo implode(";",$res_str);
Try this:
<?php
$string = '1235, 3, 1343, 5, 1234, 1';
var_dump(nth_replace($string, ',', ';', 2));
// replace all occurences of a single character with another character
function nth_replace($string, $find, $replace, $n) {
$count = 0;
for($i=0; $i<strlen($string); $i++) {
if($string[$i] == $find) {
$count++;
}
if($count == $n) {
$string[$i] = $replace;
$count = 0;
}
}
return $string;
}
?>
Result:
1235, 3; 1343, 5; 1234, 1
$find and $replace can only be one character long.Try this:
$s = "1235, 3, 1343, 5, 1234, 1";
$pcs = explode(',', $s);
$flag = false;
$res = '';
foreach ($pcs as $item) {
if (!empty($res)) {
$res .= $flag ? ',' : ';';
}
$flag = !$flag;
$res .= $item;
}
die($res);
It outputs:
1235, 3; 1343, 5; 1234, 1
try this:
$s = '1235, 3, 1343, 5, 1234, 1';
$is_second = false;
for ($i = 0; $i < strlen($s); $i++) {
if ($is_second && $s[$i] == ',') {
$s[$i] = ';';
} elseif ($s[$i] == ',') {
$is_second = true;
}
}
echo $s;
Try this:
<?php
$str = "1235, 3, 1343, 5, 1234, 1";
$data = explode(',',$str);
$counter = 0;
$new_str = "";
foreach($data as $key=>$val) {
if ($counter%2 == 0) {
$symbol=',';
}
else {
$symbol=';';
}
$new_str .= $val.$symbol;
$counter++;
}
echo $new_str;
//output::1235, 3; 1343, 5; 1234, 1;
?>
$replaced = preg_replace('/(.*),(.*),/', '$1,$2;', $strToReplace);And I agree with @deceze. You should try to solve your problems on your own./(.*?),(.*?),/instead of/(.*),(.*),/.