PHP list() -- explode() offset error

Question

Racking my brain on why this is returning PHP Error: Undefined offset: 1

public function index($hash)
    {   
        //$hash = 44253_13456789
        list($part1,$part2) = explode('_', $hash);

        $id = $part1;

        $tpl_data = array('id' => $id );
        $this->load->view('main/index', $tpl_data);
    }

the error is happening on the list() = explode(); Thanks for any insight on this.

Here is the URL for the error. http://www.onlinealbumproofing.com/beta/ipad/index/44253_1368207168

UPDATED:

Here is the controller code.

echo $hash;

list($part1,$part2) = explode('_', $hash);

$id = $part1;

$tpl_data = array('id' => $id );
$this->load->view('ipad/index', $tpl_data);

Updated Again.... OK, so looks like the error is happening on the ajax request

var id = $('body').attr('id');

    $.ajax({
        url: 'ipad/loadImages',
        type: 'POST',
        dataType: 'json',
        data: {id: id},
        success: function(json, textStatus, xhr) {
            for (var i = 0; i < json.images.length; i++) {

                //do something
            }
        }, error: function(json, textStatus) {
            console.log(textStatus);
        }
    });

Are you 1000% sure the value of $hash is "44253_13456789"? Then this should not happen! — deceze
– deceze ♦, Commented May 23, 2013 at 15:50

blue112 · Accepted Answer · 2013-05-23 15:51:49Z

2

Your problem is explode() seems like to return only one value.

list() is trying to do :

 $tmp = explode("_", $hash);
 $part1 = $tmp[0];
 $part2 = $tmp[1]; //Here is your undefined offset.

Doublecheck your $hash value.

answered May 23, 2013 at 15:51

blue112

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1 Comment

SuperNinja Over a year ago

Looks like the error is happening on the ajax request, not sure why the index function is even called again....

xdazz · Accepted Answer · 2013-05-23 15:51:35Z

0

list($part1,$part2) requires the array has two elements at least.

If $hash doesn't has a _ in it, then explode('_', $hash) won't return an array with two elements.

answered May 23, 2013 at 15:51

xdazz

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1 Comment

crowebird Over a year ago

That won't throw an offset error though, $part2 would simply be null

Woot4Moo · Accepted Answer · 2013-05-23 15:51:48Z

0

This is happening because you do not have 2 tokens being returned from your explode function. Which means you need to check the input to ensure that you will get the 2 tokens you require.

answered May 23, 2013 at 15:51

Woot4Moo

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