Calculating Pi with decimal on Python

Question

I'm trying to calculate pi with arbitrary precision on Python using one of Ramanujan's formulas: http://en.wikipedia.org/wiki/Approximations_of_%CF%80#20th_century. It basically requires lots of factorials and high-precision floating numbers division.

Here's my code so far: http://pastie.org/private/pa6ijmoowiwiw4xwiqmq

I'm getting error somewhere around the fifteenth digit of pi( 3.1415926535897930 and it should be 3.1415926535897932 ). Can you give some advice why is it happening? I' am using decimal type and the docs say that it allows arbitrary precision floating and integer numbers.

PS: It's a homework assignment so i can't use another formula. PSS: I'm using python 2.7

Thanks:)

Do you realize that Decimal(sqrt(2)) is just a complicated way of doing sqrt(2) without the Decimal? Try with Decimal(2).sqrt() — Bakuriu
– Bakuriu, Commented Jun 3, 2013 at 8:09

kirelagin · Accepted Answer · 2013-06-03 08:18:25Z

3

Use Decimal(2).sqrt() instead of Decimal(sqrt(2)).

I've checked the first 1000 digits and it seems to work fine. By the way, for some reason your code outputs 1007 decimal places instead of 1000.

edited Jun 3, 2013 at 8:18

answered Jun 3, 2013 at 8:10

kirelagin

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1 Comment

GeneralFailure Over a year ago

Yup i add precision just to be sure. Thanks a lot:)

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