jQuery Number array, everything above a certain number

Question

I have a pricing array

pricing = new Array();

pricing[1] = 35;
pricing[2] = 60;
pricing[3] = 84;
pricing[4] = 104;
pricing[5] = 120;
pricing[6] = 132;
pricing[7] = 140;
pricing[8] = 144;
pricing[9] = 153;
pricing[10] = 160;

Everything below 10 has a price, everything above 10 will have the same price as ten

It only goes to 20 so what i did originally was just repeat the price for 11 - 20. But thats wasteful, how can I tell me array that everything > 10 = 160

p.s my final version of this is condensed :)

are you saying that when accessing pricing[11], it should return 160?? like alert(pricing[11]); should alert 160?? — limovala
– limovala, Commented Jun 7, 2013 at 13:10

CD.. · Accepted Answer · 2013-06-07 13:11:54Z

2

You can leave your array as is and use a function like:

var getPrice = function(arr, index){
    return arr[index > 10 ? 10 : index];
}

answered Jun 7, 2013 at 13:11

CD..

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JustinMichaels · Accepted Answer · 2013-06-07 13:42:08Z

1

var pricing = [], i;
pricing.push(35);
pricing.push(60);
pricing.push(84);
pricing.push(104);
pricing.push(120);
pricing.push(132);
pricing.push(140);
pricing.push(144);
pricing.push(153);
for (i = 0; i < 11; i++) {
    pricing.push(160);
}

I also made a JSFiddle for this.

@CD was stating that the push function can take multiple items to append to the array. The code would look like this then:

var pricing = [], value = 160;
pricing.push(35);
pricing.push(60);
pricing.push(84);
pricing.push(104);
pricing.push(120);
pricing.push(132);
pricing.push(140);
pricing.push(144);
pricing.push(153);
pricing.push(value, value, value, value, value, value, value, value, value, value, value);

edited Jun 7, 2013 at 13:42

answered Jun 7, 2013 at 13:17

JustinMichaels

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2 Comments

CD.. Over a year ago

You can pass the push function more then one element: array.push(element1, ..., elementN)

JustinMichaels Over a year ago

Well aware of that, you could store 160 in a variable and then just pass that in 11 times in the push call but six in one and a half dozen of the other

mishik · Accepted Answer · 2013-06-07 13:11:31Z

0

i=10;
while(i--) { pricing[i+10] = 160; }

answered Jun 7, 2013 at 13:11

mishik

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Comments

gpojd · Accepted Answer · 2013-06-07 13:14:08Z

0

You missed the first entry in your array (since it is 0 based). I would change it to this:

pricing = new Array(20);

pricing[0] = 35;
pricing[1] = 60;
pricing[2] = 84;
pricing[3] = 104;
pricing[4] = 120;
pricing[5] = 132;
pricing[6] = 140;
pricing[7] = 144;
pricing[8] = 153;
pricing[9] = 160;

Then you can set the last 10 using this:

for(var x = 10; x < pricing.length; x++) {
    pricing[x] = pricing[9];
}

Example fiddle.

answered Jun 7, 2013 at 13:14

gpojd

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Comments

BeNdErR · Accepted Answer · 2013-06-07 13:17:01Z

0

pricing = new Array();
var arraySize = 100;

pricing[1] = 35;
pricing[2] = 60;
pricing[3] = 84;
pricing[4] = 104;
pricing[5] = 120;
pricing[6] = 132;
pricing[7] = 140;
pricing[8] = 144;
pricing[9] = 153;

for(var x = 10; x < arraySize; x++)
    pricing[x] = 160

console.log(pricing);

edited Jun 7, 2013 at 13:17

answered Jun 7, 2013 at 13:12

BeNdErR

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