I want to generate the following effect :
for i, j in d.items() and k, v in c.items():
print i, j, k, v
This is wrong. I want to know how can I achieve this?
Add a comment
|
2 Answers
for (i, j), (k, v) in zip(d.items(), c.items()):
print i, j, k, v
Remember the order will be arbitrary unless your dictionaries are OrderedDicts. To be memory efficient
In Python 2.x (where dict.items and zip create lists) you can do the following:
from itertools import izip
for (i, j), (k, v) in izip(d.iteritems(), c.iteritems()):
print i, j, k, v
This won't necessarily be faster, as you will observe on small lists it's faster to iterate over these intermediate lists however you will notice a speed improvement when iterating very large data structures.
In Python 3.x zip is the same as izip (which no longer exists) and dict.items (dict.iteritems no longer exists) returns a view instead of a list.
Comments
You question doesn't make it clear, whether you want to iterate the dictionaries in two nested for-loops, or side by side (as done in @jamylak's answer)
Here is the nested interpretation
from itertools import product
for (i, j), (k, v) in product(d.items(), c.items()):
print i, j, k, v
eg
>>> d={'a':'Apple', 'b':'Ball'}
>>> c={'1':'One', '2':'Two'}
>>> from itertools import product
>>> for (i, j), (k, v) in product(d.items(), c.items()):
... print i, j, k, v
...
a Apple 1 One
a Apple 2 Two
b Ball 1 One
b Ball 2 Two
1 Comment
lvc
Probably worth mentioning how the question was unclear - in particular,
product gives a similar result to iterating the dictionaries in two nested for-loops, while jamylak's answer using zip gives a similar result to two adjacent for-loops.