I have a variable length string, I just want to detect whether this string contains several characters. For example:
"sadsdd$sss^dee~"
I want to detect whether this string contains ANY of the following: $ ^ ~. How can I do that using Java string.matches?
"sadsdd$sss^dee~".matches("[^+$+~+]");
Use a pattern and a matcher for that:
Pattern pattern = Pattern.compile("[$~^]");
Matcher matcher = pattern.matcher(input);
if (matcher.find()) {
// contains special characters
} else {
// doesn't contain special characters
}
string.matches() solution.If you really must use matches then try this way
myString.matches(".*[$^~].*");
matches checks if regex can completely match string so beside part you are interested with you also need to let it match parts before and after it, which .* should handle.
How to detect if one string contains one of several characters in another string:
If you want a fast solution:
public static void main(String[] args) {
System.out.println(containsChars("sadsdd$sss^dee~", "$^~"));
}
public static boolean containsChars(String str, String chars) {
for (int i = 0; i < chars.length(); i++) {
char c = chars.charAt(i);
for (int j = 0; j < str.length(); j++) {
if (c == str.charAt(j)) {
return true;
}
}
}
return false;
}
Certainly not as small or elegant as a regular expression, but it is fast.
$^~characters or one is enough?