How do I find out if string contains multiple letters/characters using regex?

Question

In Java, is there a way to find out if string contains multiple letters/characters using Regular Expressions/ Pattern matching?

I have tried to solve my problem using below code

      String id = "A12B45";

      Pattern pattern = Pattern.compile("[A-Z]*");
      Matcher matcher = pattern.matcher(id);

      if (matcher.find()) 
              {
          System.out.println("YES---");
      } else 
              {
          System.out.println("NO---");
      }

The above code is not giving me an output which I want. When string contains more than one alphabet letter then it should return "YES---". Can you please help?

Do you mean you want to print YES--- when the string contains more than one letter consecutively? For example AK12B45 should print YES--- (because it contains A followed immediately by K) but A12B45 should print NO--- ? — Abra
– Abra, Commented Aug 9, 2019 at 6:29
Your question is not clear..What do you mean by 'string contains more than one alphabet letter ' is it anywhere in the string or consecutive occurrence? — Mukesh
– Mukesh, Commented Aug 9, 2019 at 6:41

CertainPerformance · Accepted Answer · 2019-08-09 06:19:27Z

1

Match an alphabetical character, then anything but alphabetical characters, then an alphabetical character again:

Pattern pattern = Pattern.compile("[A-Z][^A-Z]*[A-Z]");

answered Aug 9, 2019 at 6:19

CertainPerformance

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