Getting name of parent shell script

Question

I am on UBUNTU 12.04.

I have a shell script that logs the output of a certain processes. The process being logged changes depending on the parent shell script that called the logging script. I would like to write the output of this logging to a file on disk, but am having trouble naming the file.

I would love to name it according to the parent script's own name. Unfortunately I have absolutely no idea how to get that name from script. I imagine that the best way to do that would be to extract the parent PID ($PPID), and then use that to find the script name, but I also don't know how to do that.

Ignacio Vazquez-Abrams · Accepted Answer · 2013-06-24 21:08:53Z

7

Instead of jumping through hoops to do this, just have the parent open the log on say FD4. Then whenever you need to log, just write to FD4.

# parent script
exec 4>> parent.log

# child script
echo "Log me!" >&4

edited Jun 24, 2013 at 21:08

answered Jun 24, 2013 at 21:03

Ignacio Vazquez-Abrams

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2 Comments

jhc Over a year ago

Thanks! Much easier than the solution I was devising!

l0b0 Over a year ago

+1 but would be even better with the child call and FD closing.

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