Remove item from array if it exists in a 'disallowed words' array

Question

I have an array:

Array
(
    [0] => tom
    [1] => and
    [2] => jerry
)

And I also have a disallowed words array:

Array
(
    [0] => and
    [1] => foo
    [2] => bar
)

What I need to do is remove any item in the first array that also appears in the second array, in this instance for example, key 1 would need to be removed, as 'and' is in the disallowed words array.

Now I currently have this code, which does a foreach on the disallowed words and then uses array_search to find any matches:

$arr=array('tom','and','jerry');
$disallowed_words=array('and','or','if');
foreach($disallowed_words as $key => $value) {
    $arr_key=array_search($value,$array);
    if($arr_key!='') {
        unset($search_terms[$arr_key]);
    }
}

Now I know this code sucks, what I want to know is if there is a more efficient method of removing and item from an array where it exists in another array, especially if it negates using a foreach.

Matt · Accepted Answer · 2011-11-13 15:46:27Z

70

You want array_diff.

array_diff returns an array containing all the entries from array1 that are not present in any of the other arrays.

So you want something like:

$good = array_diff($arr, $disallowed_words);

edited Nov 13, 2011 at 15:46

Matt

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answered Nov 13, 2009 at 11:46

Dominic Rodger

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Comments

Kabir Hossain · Accepted Answer · 2015-05-18 11:51:30Z

0

Uses of array_dif in php://It removes values from first array if that are exist in second array.

 $foo = array(1, 5, 9, 14, 23, 31, 45);
 $bar = array(14, 31, 36);
 $data = array_diff($foo,$bar);
 print_r($data);

answered May 18, 2015 at 11:51

Kabir Hossain

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