Sed command to fetch particular string from full string

Question

I've got a file which contains lot of strings like below input. Need to extract the below output and process it further.

Input:

History={ExecAt=[2013-05-03 03:00:20,2013-05-03 03:00:23,2013-05-03 03:00:26],MId=["msgId3","msgId4","msgId5"]};

Output should be:

MId=["msgId3","msgId4","msgId5"]

using (sed 's/^.*,MId=/MId/') command i got the output like MId=["msgId3","msgId4","msgId5"]}; but still wanted the exact output (need to remove last 2 special chars }; here).

chthonicdaemon · Accepted Answer · 2013-07-25 15:23:47Z

1

This works for me:

sed 's/.*\(MId=.*\)\}.*/\1/'

answered Jul 25, 2013 at 15:23

chthonicdaemon

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choroba · Accepted Answer · 2013-07-25 15:21:48Z

1

If your grep supports the -o option, you can use it rather than sed:

grep -o 'MId=\[[^]]\+\]'

Using the same regex in sed works fine, just remove anything before and after:

sed -e 's/.*\(MId=\[[^]]\+\]\).*/\1/'

answered Jul 25, 2013 at 15:21

choroba

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