How to print specified array value

Question

I am fetch facebook user's working history, and when I print_r, I get an array like this:

Array (
    [work] => Array (
        [0] => Array (
            [employer] => Array (
                [id] => 111178415566505 
                [name] => Liputan 6 SCTV
            )
      ) [1] => Array (
            [employer] => Array (
                [id] => 107900732566334
                [name] => SCTV
            )
        )
    ) 
    [id] => 502163984
)

How do I display only the value from name, so the output will be like this:

Liputan 6 SCTV
SCTV

I used foreach, but always an error always happens.

Something like $your_variable['work'][0]['employer']['name']? — machineaddict
– machineaddict, Commented Jul 30, 2013 at 5:47

Dave Chen · Accepted Answer · 2013-07-30 05:53:32Z

1

Try this:

foreach ($array['work'] as $arr) {
    echo $arr['employer']['name']."<br>\n";
}

This is assuming your data looks like:

$array = array(
    'work' => array(
        array(
            'employer' => array('id' => 111178415566505, 'name' => 'Liputan 6 SCTV'),
        ),
        array(
            'employer' => array('id' => 107900732566334, 'name' => 'SCTV'),
        ),
    ),
    'id' => 502163984,
);

answered Jul 30, 2013 at 5:53

Dave Chen

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Comments

sudhakar · Accepted Answer · 2013-07-30 05:54:49Z

1

for instance your array variable name is $test, then you can get name value by

$test['work'][0]['employer']['name']

you can check your array structure using pre tag, like

 echo '<pre>';print_r($test);

answered Jul 30, 2013 at 5:54

sudhakar

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Comments

Orangepill · Accepted Answer · 2013-07-30 06:03:58Z

1

You can use array_reduce, implode, and closure (PHP 5.3+) to do this.

echo implode("<br/>", array_reduce($array["work"],
    function(&$arr, $v){ 
        $arr[] = $v["employer"]["name"];
    },array()
));

answered Jul 30, 2013 at 6:03

Orangepill

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1 Comment

Orangepill Over a year ago

this may very well be the most convoluted way to solve this, but its fun.

som · Accepted Answer · 2013-07-30 05:53:33Z

0

I assume $arr is working history array. You can use for Then array look like this :

for($i=0, $records = count( $arr['work']); $i < $records; $i++) {
    echo $arr['work'][$i]['employer']['name'] ."<br>";
}

Using foreach

foreach( $arr['work'] as $works) {
    echo $works['employer']['name'] ."<br>";
}

answered Jul 30, 2013 at 5:53

som

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Comments

Paul Denisevich · Accepted Answer · 2013-07-30 05:55:39Z

0

foreach ($your_array as $your_array_item)
{
    echo $your_array_item['work'][0]['employer']['name'] . '<br>';
}

answered Jul 30, 2013 at 5:55

Paul Denisevich

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Comments

DonOfDen · Accepted Answer · 2013-07-30 05:56:03Z

0

$count=count($array);

for($i=0,$i<=$count;$i++){
echo $array['work'][$i]['employer']['name'];
}

This will work.. Dynamically..

answered Jul 30, 2013 at 5:56

DonOfDen

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1 Comment

som Over a year ago

Condition should be $i < $count.

Goutam Pal · Accepted Answer · 2013-07-30 06:00:31Z

0

foreach ($array['work'] as $val_arr) {
    echo $val_arr['employer']['name']."<br />";
}

answered Jul 30, 2013 at 6:00

Goutam Pal

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