Explode and return first element of array with one line of code

Question

   $domain_parts = explode('.', preg_replace('/\s+/', '', $_GET['domain']));
   $sld = $domain_parts[0];

I am wanting to do the functionality of lines 1 and 2 into 1 line of code.

An example of what $_GET['domain'] provides is google.com

What is the cleanest way to do this in one line.

What's the obsession with fitting the most functionality onto one line? — Barmar
– Barmar, Commented Aug 3, 2013 at 7:01
Or you could always install php 5.4 and just write explode(...)[0]. — Cthulhu
– Cthulhu, Commented Aug 3, 2013 at 7:12

GautamD31 · Accepted Answer · 2013-08-03 07:06:08Z

2

You can try with list like

list($domain_parts) = explode('.', preg_replace('/\s+/', '', $_GET['domain']));

It will directly returns the $domain_parts[0].You can also try with strtok like

echo strtok(preg_replace('/\s+/', '', $_GET['domain']),  '.');

See this STRTOK

edited Aug 3, 2013 at 7:06

answered Aug 3, 2013 at 6:59

GautamD31

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bansi · Accepted Answer · 2013-08-03 07:15:54Z

0

You can also do it without regular expression like this

$sld = str_replace(' ','',substr($_GET['domain'],0,strpos($_GET['domain'],'.')));

answered Aug 3, 2013 at 7:15

bansi

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1 Comment

bansi Over a year ago

Yes. preg_replace needs lot of resource. and is not for replacing just a space. If you don't need the power of regular expressions don't use preg_ functions.

vascowhite · Accepted Answer · 2013-08-03 07:15:29Z

0

list($domain_parts) = explode('.', preg_replace('/\s+/', '', $_GET['domain']));

$domain_parts will contain the first element of the array.

You could get the second element like this:-

list(,$domain_parts) = explode('.', preg_replace('/\s+/', '', $_GET['domain']));

See list() for more details.

Or you could do this:-

$domain_parts = explode('.', preg_replace('/\s+/', '', $_GET['domain']))[0];

if you have PHP >= 5.4

edited Aug 3, 2013 at 7:15

answered Aug 3, 2013 at 6:58

vascowhite

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