'Explode' array then only display first element

Question

$value is a string of URLs. Each URL hotlinks to a JPG file and this code displays those on a page. Each URL is separated by a comma.

If I only want to display the first 1 or 2 images, what do I do? I tried to add a limiter to the explode function but I think I'm missing something because it doesn't quite work

$images = explode(',', $value);

$value = '';
foreach ($images as $im){
    $value .= '<img src="'. $im . '" />';
}

var_dump($value) ?

Halayem Anis
– Halayem Anis

2015-09-14 16:19:11 +00:00
Commented Sep 14, 2015 at 16:19 — Halayem Anis
– Halayem Anis, Commented Sep 14, 2015 at 16:19

tillz · Accepted Answer · 2015-09-14 16:19:57Z

5

array_slice is your friend!

$images = array_slice(explode(',', $value), 0, 2);
//extracts 2 elements, starting with index 0
$value = '';
foreach ($images as $im){
    $value .= '<img src="'. $im . '" />';
}

answered Sep 14, 2015 at 16:19

tillz

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tillz Over a year ago

I'm happy that I could help you! Please consider accepting my answer if it solves your question ;-)

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