PHP - complete url parser help

Question

I have been trying to find an effective url parser, php's own does not include subdomain or extension. On php.net a number of users had contributed and made this:

function parseUrl($url) {
    $r  = "^(?:(?P<scheme>\w+)://)?";
    $r .= "(?:(?P<login>\w+):(?P<pass>\w+)@)?";
    $r .= "(?P<host>(?:(?P<subdomain>[-\w\.]+)\.)?" . "(?P<domain>[-\w]+\.(?P<extension>\w+)))";
    $r .= "(?::(?P<port>\d+))?";
    $r .= "(?P<path>[\w/]*/(?P<file>\w+(?:\.\w+)?)?)?";
    $r .= "(?:\?(?P<arg>[\w=&]+))?";
    $r .= "(?:#(?P<anchor>\w+))?";
    $r = "!$r!";                                                // Delimiters

    preg_match ( $r, $url, $out );

    return $out;
}

Unfortunately it fails on paths with a '-' and I can't for the life of me workout how to amend it to accept '-' in the path name.

Thanks

Galen · Accepted Answer · 2009-11-30 17:28:50Z

1

try this...

function parseUrl($url) {
    $r  = "^(?:(?P<scheme>\w+)://)?";
    $r .= "(?:(?P<login>\w+):(?P<pass>\w+)@)?";
    $r .= "(?P<host>(?:(?P<subdomain>[-\w\.]+)\.)?" . "(?P<domain>[-\w]+\.(?P<extension>\w+)))";
    $r .= "(?::(?P<port>\d+))?";
    $r .= "(?P<path>[\w/-]*/(?P<file>[\w-]+(?:\.\w+)?)?)?";
    $r .= "(?:\?(?P<arg>[\w=&]+))?";
    $r .= "(?:#(?P<anchor>\w+))?";
    $r = "!$r!";

    preg_match ( $r, $url, $out );

    return $out;
}

i added dashes to the path and file

answered Nov 30, 2009 at 17:28

Galen

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1 Comment

Mark Over a year ago

It works exactly as I wanted... thank you for actually answering the question :)

Marko · Accepted Answer · 2009-11-30 17:14:03Z

1

It's much easier to use a existing parse_url function and then parse the subdomain from the 'host' index.

Example:

$url = 'http://username:[email protected]/path?arg=value#anchor';
$urlInfo = parse_url($url);
$host = $urlInfo['host'];
$subdomain = substr($host, 0, strpos($host, '.'));
$tld = substr($host, strrpos($host, '.') + 1);

edited Nov 30, 2009 at 17:14

answered Nov 30, 2009 at 16:36

Marko

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8 Comments

Mark Over a year ago

can you suggest how I might go about that?

Dominic Rodger Over a year ago

@Mark - to do what? What are you trying to achieve?

Mark Over a year ago

I am looking to get the subdomain, tld, domain, path and arguments of a url. parse_url does not allow for subdomain or tld.

Galen Over a year ago

that will fail for tlds such as .co.uk

Pekka Over a year ago

Well technically, .co.uk is not a TLD, only .uk is. If I understand it right, you will have to keep a manual list for those cases anyway - there are lots other "quasi-tld"s like .co.at, .co.in and so on.

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