I need a sentence if...else.. that verify if the filename curbing a string specifies in bash
for j in `ls `
do
if [ "${j:(-3)}" == ".gz" ]; then
Cmd="zcat"
elif [ "${j:(-4)}" == ".bz2" ]; then
Cmd="bzcat"
else
Cmd="cat"
fi
if [ $j ***contains*** "string1"]; then
$cmd $j | awk -F"," '{print $4}'
elif [ $j *contains* "string2" ]; then
$cmd $j | awk -F"," '{print $2}'
fi
done
Use double brackets, which support wildcards:
if [[ $j == *string1* ]]; then
Also, don't parse ls; use a glob instead:
Instead of
for j in `ls `
use
for j in *
If you wan't the match to be case-insensitive, you can set the shopt -s nocasematch option:
shopt -s nocasematch
if [[ $j == *string1* ]]; then
shopt -s nocasematch to do case-insensitive matchesThe =~ operator does what you want.
I personally would use find and xargs though.
find . -name "*.gz" -print0 | xargs -I{} -0 gzip -dc {} | cut -f, -d4
find . -name "*.bz2" -print0 | xargs -I{} -0 bzip2 -dc {} | cut -f, -d4
Use bash's regex capabilities here. So instead of;
if [ $j ***contains*** "string1"]; then
Use:
if [[ "$j" =~ \bstring1\b ]]; then
PS: Note use of \b (word boundaries) to make sure you don't match string123 in $j.
Also instead of using ls:
for j in `ls `
You should better use:
for j in *
