How to use BigInteger value to initialize String Array?

Question

I am writing a program and stuck with below issue of BigInteger.

BigInteger noOfCombinationForWordsToBeSearchedBig = factorial(noOfWordsToBeSearched);
String[][] combinationForWordsToBeSearched = new String[ noOfCombinationForWordsToBeSearchedBig.longValue()][noOfWordsToBeSearched];

I want to initialize the String[][] array with value of noOfCombinationForWordsToBeSearchedBig .

For examaple, i am finding factorial of 17 which is big integer.

Please advise.

Even if Java allowed you to initialize an array this big, do you have enough ram to store 17!=355687428096000 pointers to String? Assuming each pointer is 8 byte, you'd need 2845TB of RAM. — Giulio Franco
– Giulio Franco, Commented Aug 24, 2013 at 13:56

Community · Accepted Answer · 2017-05-23 11:49:51Z

4

Array index can not be more than Integer.MAX_VALUE in Java. In fact its much less than Integer.MAX_VALUE. So actually you can not put BigInteger as the size parameter, while creating an array.

For details see here.

edited May 23, 2017 at 11:49

CommunityBot

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answered Aug 24, 2013 at 13:38

Sazzadur Rahaman

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1 Comment

Kevin Bhuva Over a year ago

Thanks. forgot this concept.

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