PHP Array during echo

Question

I have an assignment to do but am having trouble understanding the given psuedocode :/

<?php
$bucket = new array();
print $bucket->addrocks('Rock1')->addrocks('rock2')-
>addrocks('Rock3');

echo "<h1>My Bucket</h1>";
echo "<ul>";
foreach($bucket as $rock){
echo "<li>". $rock ."</li>";
}
echo "</ul>";
?>

Now my trouble starts with understanding how they want me to construct the array after the "print" call? i am not looking for a direct answer to this just maybe a tutorial link or a finger in the right direction

Thank you in advance

man what you are doing is correct , the problem is that your array is empty and syntax is incorrect , delete new — Charaf JRA
– Charaf JRA, Commented Sep 12, 2013 at 21:27
looks like $bucket[]='Rock1'; $bucket[]='Rock2'; $bucket[]='Rock3'; to me. — user557846
– user557846, Commented Sep 12, 2013 at 21:28
$bucket->addrocks shall return its same object; Also take a look at php.net/manual/en/language.oop5.magic.php#object.tostring — Dennis Ziolkowski
– Dennis Ziolkowski, Commented Sep 12, 2013 at 21:28
What exactly is this supposed to do? You are treating $bucket as an object that has a method called addrocks(), but you've created it as an empty array. The rest of the code is fine in that you are creating an unordered list and iterating through each item in $bucket and printing them. — Chris Rasco
– Chris Rasco, Commented Sep 12, 2013 at 21:29

Ryan · Accepted Answer · 2013-09-12 21:30:18Z

3

In PHP, new is only used for instantiating objects Furthermore, array is a reserved word in PHP, so name your class something else. To instantiate an array in PHP you do this:

 $my_array = array();

Now to add items to the array you would do this:

 $my_array[] = "Rock 1";
 $my_array[] = "Rock 2";
 $my_array[] = "Rock 3";

To traverse the array you can use any type of loop, but usually you would just use a foreach loop.

For example:

 foreach($my_array as $key => $value) {
   echo $value . "<br />";
 }

answered Sep 12, 2013 at 21:30

Ryan

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8 Comments

Starx Over a year ago

You did not use new keyword also.

Charaf JRA Over a year ago

@Starx when trying this , class array { } it's not working array is special word ,this can't be done

Daryl Gill Over a year ago

Have you stopped to think, maybe he was going for a STD Array class?

Starx Over a year ago

@FaceOfJock, No I am responding to his comment about Wrong. you do not use new in the other answer by Joren.

Starx Over a year ago

@DarylGill, How do you instantiate a STD Array class?

|

Joren · Accepted Answer · 2013-09-12 21:30:25Z

1

The problem lies in the array construction. This is how one constructs an array in PHP:

one by one:

$bucket = array();
$bucket[] = "Rock1";
$bucket[] = "Rock2";
$bucket[] = "Rock3";

All at once:

$bucket = array("Rock1","Rock2","Rock3");

The documentation: http://php.net/manual/en/language.types.array.php

answered Sep 12, 2013 at 21:30

Joren

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Comments

Starx · Accepted Answer · 2013-09-12 21:36:57Z

1

Well unlikely but may be the array is not an construct but an class in your pseudocode. My assumptions depend on the use of new keyword and the user of -> and addrocks which looks like a method.

So, create a class called array (stupid I know) and get going.

However the user of foreach($bucket) also shows that it expects $bucket to be array. So decide wisely :)

May be use a magic method called __toString() inside the class and return back the array.

edited Sep 12, 2013 at 21:36

answered Sep 12, 2013 at 21:30

Starx

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1 Comment

Charaf JRA Over a year ago

maybe he has toString that returns array ??

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