How to avoid dangling reference in array subscription operator in some vector implementation below? If realloc changes the pointer then references previously obtained from operator[] are no longer valid. I cannot use new/delete for this. I have to use malloc/realloc/free.
template <class T>
class Vector
{
public:
typedef size_t size_type_;
...
T& operator[] (const size_type_);
void push_back (const T&);
...
private:
const size_type_ page_size_;
size_type_ size_;
size_type_ capacity_;
T* buffer_;
};
template<class T>
inline
T&
some_namespace::Vector<T>::operator[] (const size_type_ index)
{
ASSERT(index < size_);
return buffer_[index];
}
template<class T>
inline
void
some_namespace::Vector<T>::push_back(const T& val)
{
if (size_ >= capacity_)
{
capacity_ += page_size_;
T* temp = (T*)(realloc(buffer_, capacity_*sizeof(T)));
if (temp != NULL)
{
buffer_ = temp;
}
else
{
free(buffer_);
throw some_namespace::UnexpectedEvent();
}
}
buffer_[size_++] = val;
}
By the way, the source of dangling reference in the code was this:
v_.push_back(v_[id]);
where v_ is an instance of Vector. To guard against this the new push_back is:
template<class T>
inline
void
some_namespace::Vector<T>::push_back(const T& val)
{
if (size_ >= capacity_)
{
const T val_temp = val; // copy val since it may come from the buffer_
capacity_ += page_size_;
T* temp = (T*)(realloc(buffer_, capacity_*sizeof(T)));
if (temp != NULL)
{
buffer_ = temp;
}
else
{
free(buffer_);
throw some_namespace::UnexpectedEvent();
}
buffer_[size_++] = val_temp;
}
else
{
buffer_[size_++] = val;
}
}