Return duplicate values in array in Javascript

Question

I am trying to sort out an array and returning the duplicate values. So i know if the value in this case a date exists one or more times. I have been searching and I do only find how to delete the values.

I would like to just return the value that exists one or more times in the array.

This far I have come so long:

var singelbokningar = [];
   $.each(bokadeDatumDone, function(i, el){
   if($.inArray(el, singelbokningar) > -1) singelbokningar.push(el);
});

But it returns a new array without the duplicates.

How should I do?

Joseph Silber · Accepted Answer · 2013-10-02 15:34:16Z

1

Just create another array to hold you duplicates:

var singelbokningar = [];
var duplicates = [];

$.each(bokadeDatumDone, function(i, el) {
   if ( $.inArray(el, singelbokningar) > -1 ) singelbokningar.push(el);
   else duplicates.push(el);
});

answered Oct 2, 2013 at 15:34

Joseph Silber

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1 Comment

Jonas Olaussen Over a year ago

Yes! Thank you! There is only one problem with our code and that is: It should be: ===1 Not > 1 But That is my fault! But thank you!

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