Is it possible to define method argument with default values in Java?

Question

Really want to initialise some arguments in a Java method eg

public void delete(String name, int user_id=0) { //method body }

so that the user_id does not have to necessarily be passed. But i'm getting this Eclipse error that the token is invalid. How do i go about this?

Maxim Shoustin · Accepted Answer · 2013-10-10 10:48:54Z

13

Java != PHP.

But you can write:

public void delete(String name){
  delete(name, 0);
}

public void delete(String name, int user_id){/* ...*/}

answered Oct 10, 2013 at 10:48

Maxim Shoustin

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2 Comments

gthuo Over a year ago

oops! i think my brain is still not healed from the PHP infections. I wanted to avoid having many methods..but its ok

eatSleepCode Over a year ago

There is no way in java to have a default parameter. The only way is to have multiple methods.

kayleighsdaddy · Accepted Answer · 2015-07-21 03:24:42Z

0

You can uses generic bounded methods. I kind of think they are messy and only recommend it if you actually have a deed to do it.

https://docs.oracle.com/javase/tutorial/java/generics/boundedTypeParams.html

I've found youtube videos on how to do this and it does work. But like I said, personally if it is only 2 or 3 methods you are making I would make the methods, cause this is messy.

answered Jul 21, 2015 at 3:24

kayleighsdaddy

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