Does Java support default parameter values? [duplicate]

No, but you can use the Builder Pattern, as described in this Stack Overflow answer.

As described in the linked answer, the Builder Pattern lets you write code like

Student s1 = new StudentBuilder().name("Eli").buildStudent();
Student s2 = new StudentBuilder()
                 .name("Spicoli")
                 .age(16)
                 .motto("Aloha, Mr Hand")
                 .buildStudent();

in which some fields can have default values or otherwise be optional.

Sadly, no.

Unfortunately, yes.

void MyParameterizedFunction(String param1, int param2, bool param3=false) {}

could be written in Java 1.5 as:

void MyParameterizedFunction(String param1, int param2, Boolean... params) {
    assert params.length <= 1;
    bool param3 = params.length > 0 ? params[0].booleanValue() : false;
}

But whether or not you should depend on how you feel about the compiler generating a

new Boolean[]{}

for each call.

For multiple defaultable parameters:

void MyParameterizedFunction(String param1, int param2, bool param3=false, int param4=42) {}

could be written in Java 1.5 as:

void MyParameterizedFunction(String param1, int param2, Object... p) {
    int l = p.length;
    assert l <= 2;
    assert l < 1 || Boolean.class.isInstance(p[0]);
    assert l < 2 || Integer.class.isInstance(p[1]);
    bool param3 = l > 0 && p[0] != null ? ((Boolean)p[0]).booleanValue() : false;
    int param4 = l > 1 && p[1] != null ? ((Integer)p[1]).intValue() : 42;
}

This matches C++ syntax, which only allows defaulted parameters at the end of the parameter list.

Beyond syntax, there is a difference where this has run time type checking for passed defaultable parameters and C++ type checks them during compile.

No, but you can very easily emulate them. What in C++ was:

public: void myFunction(int a, int b=5, string c="test") { ... }

In Java, it will be an overloaded function:

public void myFunction(int a, int b, string c) { ... }

public void myFunction(int a, int b) {
    myFunction(a, b, "test");
}

public void myFunction(int a) {
    myFunction(a, 5);
}

Earlier was mentioned, that default parameters caused ambiguous cases in function overloading. That is simply not true, we can see in the case of the C++: yes, maybe it can create ambiguous cases, but these problem can be easily handled. It simply wasn't developed in Java, probably because the creators wanted a much simpler language as C++ was - if they had right, is another question. But most of us don't think he uses Java because of its simplicity.

You can do this is in Scala, which runs on the JVM and is compatible with Java programs. http://www.scala-lang.org/

i.e.

class Foo(var prime: Boolean = false, val rib: String)  {}

Instead of using:

void parameterizedMethod(String param1, int param2) {
    this(param1, param2, false);
}

void parameterizedMethod(String param1, int param2, boolean param3) {
    //use all three parameters here
}

You could utilize java's Optional functionality by having a single method:

void parameterizedMethod(String param1, int param2, @Nullable Boolean param3) {
    param3 = Optional.ofNullable(param3).orElse(false);
    //use all three parameters here
}

The main difference is that you have to use wrapper classes instead of primitive Java types to allow null input.Boolean instead of boolean, Integer instead of int and so on.

No, but the simplest way to implement this is:

public myParameterizedFunction(String param1, int param2, Boolean param3) {

    param3 = param3 == null ? false : param3;
}

public myParameterizedFunction(String param1, int param2) {

    this(param1, param2, false);
}

or instead of the ternary operator, you can use if:

public myParameterizedFunction(String param1, int param2, Boolean param3) {

    if (param3 == null) {
        param3 = false;
    }
}

public myParameterizedFunction(String param1, int param2) {

    this(param1, param2, false);
}

I might be stating the obvious here but why not simply implement the "default" parameter yourself?

public class Foo() {
        public void func(String s){
                func(s, true);
        }
        public void func(String s, boolean b){
                //your code here
        }
}

for the default, you would either use

func("my string");

and if you wouldn't like to use the default, you would use

func("my string", false);

It is not supported in java as in other language for ex. Kotlin.

As Scala was mentioned, Kotlin is also worth mentioning. In Kotlin function parameters can have default values as well and they can even refer to other parameters:

fun read(b: Array<Byte>, off: Int = 0, len: Int = b.size) {
    ...
}

Like Scala, Kotlin runs on the JVM and can be easily integrated into existing Java projects.

No. In general Java doesn't have much (any) syntactic sugar, since they tried to make a simple language.

No.

You can achieve the same behavior by passing an Object which has smart defaults. But again it depends what your case is at hand.

It is not supported but there are several options like using parameter object pattern with some syntax sugar:

public class Foo() {
    private static class ParameterObject {
        int param1 = 1;
        String param2 = "";
    }

    public static void main(String[] args) {
        new Foo().myMethod(new ParameterObject() {{ param1 = 10; param2 = "bar";}});
    }

    private void myMethod(ParameterObject po) {
    }
}

In this sample we construct ParameterObject with default values and override them in class instance initialization section { param1 = 10; param2 = "bar";}

You may use Java Method Invocation Builder to automatically generate the builder with default values.

Just add @GenerateMethodInvocationBuilder to the class, or interface, and the @Default to parameters in methods where you want default values. A builder will be generated at compile time, using the default values that you specified with your annotations.

@GenerateMethodInvocationBuilder
public class CarService {
 public CarService() {
 }

 public String getCarsByFilter(//
   @Default("Color.BLUE") Color color, //
   @Default("new ProductionYear(2001)") ProductionYear productionYear,//
   @Default("Tomas") String owner//
 ) {
  return "Filtering... " + color + productionYear + owner;
 }
}

And then you can invoke the methods.

CarService instance = new CarService();
String carsByFilter = CarServiceGetCarsByFilterBuilder.getCarsByFilter()//
  .invoke(instance);

Or set any of the default values to something else.

CarService instance = new CarService();
String carsByFilter = CarServiceGetCarsByFilterBuilder.getCarsByFilter()//
  .withColor(Color.YELLOW)//
  .invoke(instance);

If you really want to, you can check it manually by using null:

public MyParameterizedFunction(String param1, int param2, boolean param3)
{
    if(param3 == null) {
        param3 = false;
    }
}

However i heavily recommend using something else, like overloading or a static factory. Maybe you can get away with this, but it can lead to unexcspected behavior. For example you could have an error in your code, so that your boolean never gets a value. In this case you would not get a NullPointerException. Instead it will look like it was set to false, which can be very confusing to debug.

Try this solution:

public int getScore(int score, Integer... bonus)
{
    if(bonus.length > 0)
    {
        return score + bonus[0];
    }

    return score;
}

constructor like for method

static void popuping() {
    popuping("message", "title");
}
static void popuping(String message) {
    popuping(message, "title");
}
static void popuping(String message, String title){
    JOptionPane.showMessageDialog(null, message,
            title, JOptionPane.INFORMATION_MESSAGE);
}

A similar approach to https://stackoverflow.com/a/13864910/2323964 that works in Java 8 is to use an interface with default getters. This will be more whitespace verbose, but is mockable, and it's great for when you have a bunch of instances where you actually want to draw attention to the parameters.

public class Foo() {
    public interface Parameters {
        String getRequired();
        default int getOptionalInt(){ return 23; }
        default String getOptionalString(){ return "Skidoo"; }
    }

    public Foo(Parameters parameters){
        //...
    }

    public static void baz() {
        final Foo foo = new Foo(new Person() {
            @Override public String getRequired(){ return "blahblahblah"; }
            @Override public int getOptionalInt(){ return 43; }
        });
    }
}

I've now spent quite some time to figure out how to use this with methods that return values, and I haven't seen any examples so far, I thought it might be useful to add this here:

int foo(int a) {
    // do something with a
    return a;
}

int foo() {
    return foo(0); // here, 0 is a default value for a
}

This is how I did it ... it's not as convenient perhaps as having an 'optional argument' against your defined parameter, but it gets the job done:

public void postUserMessage(String s,boolean wipeClean)
{
    if(wipeClean)
    {
        userInformation.setText(s + "\n");
    }
    else
    {
        postUserMessage(s);
    }
}

public void postUserMessage(String s)
{
    userInformation.appendText(s + "\n");
}

Notice I can invoke the same method name with either just a string or I can invoke it with a string and a boolean value. In this case, setting wipeClean to true will replace all of the text in my TextArea with the provided string. Setting wipeClean to false or leaving it out all together simply appends the provided text to the TextArea.

Also notice I am not repeating code in the two methods, I am merely adding the functionality of being able to reset the TextArea by creating a new method with the same name only with the added boolean.

I actually think this is a little cleaner than if Java provided an 'optional argument' for our parameters since we would need to then code for default values etc. In this example, I don't need to worry about any of that. Yes, I have added yet another method to my class, but it's easier to read in the long run in my humble opinion.

NO, But we have alternative in the form of function overloading.

called when no parameter passed

void operation(){

int a = 0;
int b = 0;

} 

called when "a" parameter was passed

void operation(int a){

int b = 0;
//code

} 

called when parameter b passed

void operation(int a , int b){
//code
} 

There are half a dozen or better issues such as this, eventually, you arrive at the static factory pattern ... see the crypto API for that. Sort difficult to explain, but think of it this way: If you have a constructor, default or otherwise, the only way to propagate state beyond the curly braces is either to have a Boolean isValid; ( along with the null as default value v failed constructor ) or throw an exception which is never informative when getting it back from field users.

Code Correct be damned, I write thousand line constructors and do what I need. I find using isValid at object construction - in other words, two-line constructors - but for some reason, I am migrating to the static factory pattern. I just seem you can do a lot if you in a method call, there are still sync() issues but defaults can be 'substituted' better ( safer )

I think what we need to do here is address the issue of null as default value vis-a-vis something String one=new String(""); as a member variable, then doing a check for null before assigning string passed to the constructor.

Very remarkable the amount of raw, stratospheric computer science done in Java.

C++ and so on has vendor libs, yes. Java can outrun them on large scale servers due to it's a massive toolbox. Study static initializer blocks, stay with us.

One idea is to use String... args

public class Sample {
   void demoMethod(String... args) {
      for (String arg : args) {
         System.out.println(arg);
      }
   }
   public static void main(String args[] ) {
      new Sample().demoMethod("ram", "rahim", "robert");
      new Sample().demoMethod("krishna", "kasyap");
      new Sample().demoMethod();
   }
}

Output

ram
rahim
robert
krishna
kasyap

from https://www.tutorialspoint.com/Does-Java-support-default-parameter-values-for-a-method

You can use the following-

public void mop(Integer x) {
  // Define default values
        x = x == null ? 200 : x;
}

The Straight answer is no.

These answers are pretty old and mainly discuss the alternatives we can have even if java doesn't have a straight way of the default method parameter.

we can deal with this scenario easily with functional Programming in java.

we can utilize the method currying of java functional programming and I think it can be best utilized for such scenarios where we need to have default parameters.

we may need a default parameter in the following situations... Example: Create a method that works on Two different objects and returns the computation

int mutiply(int a,int b){

      return a*b;

  }

if we want to have a method to get multiply by 2, we will have to Override the method like below

int mutiply(int a){

      mutiply(a, 2); // as can not write mutiply(int a,b=2)

  }

Above, 2 is a default value for b, but it's going to be fixed. what if we want to have multiplied by three, now we cannot overload this further and it does feel odd to have multiple methods like this.

This is when we can utilize the method currying technique.

method Currying is the way of converting multi-parameter functions into multiple functions each accepting a single parameter.

Steps to create a Curried method

1. Write a function that accepts a single parameter and returns another function, like below.

    Function<Integer,Function<Integer,Integer>> mutiply = a->{
    return  b -> a*b;
    };
   

2. Let's Simplify and understand the above method.

The Above method accepts only One integer Argument and returns another function with one parameter a as the default value and b as a variable. In case you are confused and start thinking how the method can use a variable from the caller function and don’t know about closures …

"A closure is a function that refers to a free variable in its lexical context." So here, in this case, closure is the returned function when operated on variable multiply and it has a free variable a that has the lexical context of the caller function.

3. Return the multiply method or fix the default value for one of the parameters.

    //multiply is defined in the first step
    mutiplyByTwo = mutiply.apply(2)
   
    mutiplyByThree = mutiply.apply(3);
   
    mutiplyByFour = mutiply.apply(4);;
   

   And so on …

4. Pass the second variable to the returned function to get the result.

   mutiplyByTwo.apply(2);//results 
   mutiplyByTwo.apply(3);//results 6
   
   
   
    mutiplyByThree.apply(2);//results 6
    mutiplyByThree.apply(3);//results 9
   
    mutiplyByFour.apply(2);//results 8
    mutiplyByFour.apply(3);//results 124
   

You can find my original post here ... https://www.linkedin.com/pulse/can-we-have-default-method-parameter-java-rajat-singh/?trackingId=yW84I1fzT6WGStrNPAWn4w%3D%3D