Simple PHP class, undefined variable?

Question

I'm learning about classes and objects in PHP, and I'm getting really confused. This is what I have so far:

<?php

class ipInfo {
    public $test1 = 'test';
}

$test = new ipInfo();
echo $test->$test1;

?>

Whenever I run it, I get these errors:

Notice: Undefined variable: test1 in //// on line 9

Fatal error: Cannot access empty property in //// on line 9

This question appears to be off-topic because the right syntax can be found in the manual — Ja͢ck
– Ja͢ck, Commented Oct 18, 2013 at 1:59

Fluffeh · Accepted Answer · 2013-10-18 01:50:12Z

16

Object properties don't need the second $ (unless you are using variable varibles).

echo $test->test1;

You use the $ to reference the variable and then the -> to specify which propery you are looking at.

If you on the other hand have a variable with the value of test1 called $var you could do this:

$var='test1';
echo $test->$var;

Which would work as the code would interpret the VALUE inside the $var and assume you meant that property.

answered Oct 18, 2013 at 1:48

Fluffeh

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Comments

immulatin · Accepted Answer · 2013-10-18 01:47:50Z

2

You dont access them with a $ sign:

try:

echo $test->test1;

answered Oct 18, 2013 at 1:47

immulatin

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