Undefined Variable PHP Class

Question

I'm trying to debug a class that I made. It always breaks and throw undefined variable on the logs I couldn't find a solution because I don't know what I'm doing wrong, I think it should work but not.

The undefined variable is on the erase() function, not in the show() function

class pepe{
 private $array = array();

 function show(){
   $this->erase();
   print_r($this->array);
 }
 function erase(){
   print_r($this->array); 
 }
}

$o = new pepe();
$s = $o->show();

It should work, i posted a simple example, in my code isnt working pastebin.com/PsTXeJ6D On line 110 it says undefined variable — fabianGarga
– fabianGarga, Commented May 21, 2015 at 5:37
Found the error made by me, it's not good to work at 3am. In my code i have $o->$array(); Thanks a lot people! — fabianGarga
– fabianGarga, Commented May 21, 2015 at 5:53

Tewdyn · Accepted Answer · 2015-05-21 05:38:23Z

2

class pepe{

private $array = array();

 

function show(){

$this->erase();

print_r($this->array);

}

function erase(){

print_r($this->array); 

}

}

 

$o = new pepe();

$s = pepe->show();

Why are you calling pepe here? Should be like this:

  class pepe{
    private $array = array();

 function show(){
   $this->erase();
   print_r($this->array);
 }
 function erase(){
   print_r($this->array); 
 }
}

$o = new pepe();
$s = $o->show();

You have to call

$o->show()

because you've assigned pepe to

$o

edited May 21, 2015 at 5:38

answered May 21, 2015 at 5:30

Tewdyn

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