I would like to compare the 3 javascript variable values and they are equal, need to perform a function.
if(vcount === tcount === lcount){
//do something;
}
and (as per this previous answer)
if((vcount == tcount) && (tcount == lcount)){
//do something;
}
But its not working for me.
consider the following code-
1===1===1
As === operator is left-right associative hence the first part that is 1===1 is evaluated first.
1===1 returns true. then there is the following comparison
true===1
Which is definitely false because boolean true is not same as 1 because === considers value as well as datatype.
boolean it will definitely return false if you use === to compare them. Hence you should always use the 2nd syntax to compare any 3 values.Try with Conditional(Ternary) Operator (?:) which will help. Please refer below example This is one way of alternative solution
<!DOCTYPE html>
<html>
<body>
<button onclick="myFunction()">Try it</button>
<p id="demo"></p>
<script>
function myFunction()
{
document.getElementById("demo").innerHTML= getResult(7,5,5);
}
function getResult(x,y,z){
return x===y?x===z?true:false:false;
}
</script>
</body>
</html>
Apart from what others have said, verify your variables are the correct type. For example, one might be a character and another other is an integer. Try to verify they are all the same by doing toString(value), or parseInt(value,10).
There are multiple ways to do this. I prefer this way to work with n variables
function isEqual1() {
var val = arguments[0],
equal = true;
for (var i = 0; i < arguments.length; i++) {
equal = (arguments[i] === val);
if (!equal) return false;
}
return equal;
}
else
function isEqual2() {
var args = Array.prototype.slice.call(arguments, 0);
var equal = args.join(',').replace(new RegExp(args[0], "ig"), '').replace(/,/g, "");
return equal.length == 0;
}
Results
console.log(isEqual1(1, true, false, "xyz"));
console.log(isEqual1(true, true, true, true));
console.log(isEqual2(true, 123, true, true));
console.log(isEqual2(true, true, true, true));
A more functional approach is to create a set and than check the size of the set:
const things = new Set(["b","b","b"]);
if (things.size === 1 ){
console.log('Only one thing!');
}
(vcount === tcount) && (tcount === lcount)What do you mean by not working.