cannot find value in array

Question

I can't see where I am wrong with this code so I kindly ask for your help. I have two arrays:

Array (
    [0] => Array (
        [description] => Generali di Proprieta'
        [idmov] => 34
        [mov] => Manutenzioni
        [total] => 8000
    )
    [1] => Array (
        [description] => Generali di Proprieta'
        [idmov] => 35
        [mov] => Assicurazioni
        [total] => 6000
    )
    [2] => Array (
        [description] => Generali di Proprieta'
        [idmov] => 36
        [mov] => Cancelleria Postali
        [total] => 1850
    )
    [3] => Array (
        [description] => Generali di Proprieta'
        [idmov] => 37
        [mov] => Bancarie passive
        [total] => 700
    )
    [4] => Array (
        [description] => Generali di Proprieta'
        [idmov] => 38
        [mov] => Amministrazione
        [total] => 15000
    )
)

and

Array (
    [0] => Array (
        [center] => 8
        [caus] => 34
        [total] => 38175.04
    )
    [1] => Array (
        [center] => 8
        [caus] => 35
        [total] => 6132.00
    )
    [2] => Array (
        [center] => 8
        [caus] => 36
        [total] => 223.80
    )
    [3] => Array (
        [center] => 8
        [caus] => 37
        [total] => 114.70
    )
    [4] => Array (
        [center] => 8
        [caus] => 38
        [total] => 14625.07
    )
    [5] => Array (
        [center] => 8
        [caus] => 39
        [total] => 7450.48
    )

I use this function

function searchForId($id, $array) {
   foreach ($array as $key => $val) {
       if ($val['caus'] === $id) {
           return $key;
       }
   }
   return null;
}

to look in array B for each item of array A with this code:

for($i=0;$i<$length;$i++){
    if(searchForId($voce_bdg[$i]['idmov'], $voce_actual)){
        $key=searchForId($voce_bdg[$i]['idmov'], $voce_actual);
        $actual=$voce_actual[$key]['importo'];
        echo '<td class="report">'.number_format($actual,2,',','.').'</td>';
     }else{
        echo '<td class="report">0,00</td>';
    }
}

It works for every item like a charm except for the first item where it returns 0.

Where am I wrong??

Thanks in advance for your help! Lelio

Name variables in English that will make it more understandable for others. — Leri
– Leri, Commented Oct 21, 2013 at 15:30
AAAAAAHHHHH! I formatted your question readably, why did you undo it? — Barmar
– Barmar, Commented Oct 21, 2013 at 15:36
Sorry, I just edited the variables names. Probably we did it concurrently :( — user2399035
– user2399035, Commented Oct 21, 2013 at 15:40

Sutandiono · Accepted Answer · 2013-10-21 15:48:14Z

1

PHP treats the index 0 as a false. As such, if you find your result in index zero, it won't pass the if() statement you have.

Since your function returns null if no record found, why not try to check for null?

for($i = 0; $i < $length; $i++)
{
    // Use is_null() check below. If it is not null, it is found.
    // Also, instead of doing searchForId() twice, just do it once and check for the result.

    $key = searchForId($voce_bdg[$i]['idmov'], $voce_actual);

    if(! is_null ($key))
    {
        $actual = $voce_actual[$key]['importo'];
        echo '<td class="report">'.number_format($actual,2,',','.').'</td>';
    }
    else
    {
        echo '<td class="report">0,00</td>';
    }
}

answered Oct 21, 2013 at 15:48

Sutandiono

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4 Comments

user2399035 Over a year ago

It works, thank you. "PHP treats the index 0 as a false. As such, if you find your result in index zero, it won't pass the if() statement you have." Never realized before! Thank you again!

dishwasherWithProgrammingSkill Over a year ago

if this works then its fine other wise you can simply use in_array(searchitem,arraylist). put what item from array 1 you want to search in param 1 and put array 2 in param 2. php.net/manual/en/function.in-array.php

Sutandiono Over a year ago

@dishwasherWithProgrammingSkill You cannot use in_array() in this case, because: 1. The second array is 2-dimensional; 2. We want to look at the inner array with key 'caus'; 3. We want to retrieve the key where the search item is found to be used later.

dishwasherWithProgrammingSkill Over a year ago

my bad didn't realize it was a multidimensional array, guess I should stick to dishwashing ;D

Peminator · Accepted Answer · 2013-10-21 15:33:08Z

0

try replacing operator === for ==

answered Oct 21, 2013 at 15:33

Peminator

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1 Comment

user2399035 Over a year ago

Already tried. No changes. The first idmov=34 that match caus=34 provides no results. All the following are ok both with === and ==

Bibear · Accepted Answer · 2013-10-21 15:47:45Z

0

It does return something. It return 0 since the key is 0. But your if() interpret it as a "false"

change

if(searchForId($voce_bdg[$i]['idmov'], $voce_actual)){

with

if(searchForId($voce_bdg[$i]['idmov'], $voce_actual) != null){

answered Oct 21, 2013 at 15:47

Bibear

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