jQuery objects comparison

Question

According to the jQuery documentation, "Not All jQuery Objects are Created ===."

"An important detail regarding this "wrapping" behavior is that each wrapped object is unique. This is true even if the object was created with the same selector or contain references to the exact same DOM elements."

documentation

I know how to work around this but why is this the case? Is this some specific way that JavaScript behaves?

nrabinowitz · Accepted Answer · 2013-10-21 23:25:07Z

4

Yes. Every object in JS is unique, in that o1 === o2 will not be true unless o1 and o2 are pointers to the same object.

{ foo: 1 } === { foo: 1 }; // false

So jQuery objects simply follow this same rule:

var jq1 = $('.foo');
var jq2 = $('.foo');
jq1 === jq2; // false

The only exception is if you have variables that actually point to the same jQuery object:

var jq3 = jq1;
jq3 === jq1; // true

answered Oct 21, 2013 at 23:25

nrabinowitz

55.7k10 gold badges152 silver badges169 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

jQuery objects comparison

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related