PHP strtotime error when convert some date string to datetime value

Question

I have a trouble with strtotime in php.

$j = "2013-10-27";
for ($x = 0; $x < 100; $x++) {
  $j = date('Y-m-d', strtotime($j) + 86400);
  echo ' '.$j.' <br/>';
}

As the code is self explained, it will add one day to $j and then display to browser. But when $j = "2013-10-27", it prints just one result ("2013-10-27"). If I change $j to another date, this does work, but also stucks at this date (and some other date).

I have written other code to do this work. But does anyone know why it fails, or my code is wrong?

Thank you.

your code showing one result 100 times.where did you use $i ? — Mahmood Rehman
– Mahmood Rehman, Commented Nov 1, 2013 at 4:49
Well, I don't use $i, but $x just for counting (in this code). — William Truong
– William Truong, Commented Nov 1, 2013 at 4:53
I have tested on PHP 5.4.19, PHP 5.3.1 (with XAMPP on Windows 8), and got the same result. So I decide to ask you guys. — William Truong
– William Truong, Commented Nov 1, 2013 at 4:56

Paul Creasey · Accepted Answer · 2013-11-01 04:55:43Z

4

This is because you are in a timezone with daylight savings time, and on the 27th October at 1 AM the time reverted to midnight, making it a 25 hour day.

This can be reproduced by setting the timezone:

<?php
date_default_timezone_set('Europe/London');
$j = "2013-10-27";
for ($x = 0; $x < 100; $x++) {
  $j = date('Y-m-d', strtotime($j) + 86400);
  echo ' '.$j.' <br/>';
}

http://codepad.viper-7.com/uTbNWf

answered Nov 1, 2013 at 4:55

Paul Creasey

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Comments

Phil · Accepted Answer · 2013-11-01 04:55:42Z

3

strtotime has too many limitations in my opinion. Use the more recent DateTime lib instead

$j = new DateTime('2013-10-27');
$interval = new DateInterval('P1D');
for ($x = 0; $x < 100; $x++) {
    $j->add($interval);
    echo $j->format('Y-m-d'), '<br>';
}

answered Nov 1, 2013 at 4:55

Phil

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1 Comment

Phil Over a year ago

Consequentially, this takes care of the DST switch mentioned in Paul's answer

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