strtotime conversion with variable error

Question

I am getting wrong output i.e. 1194908400 None of this is working i.e. I tried to put double quotes around variable, tried without quotation marks. result is same and wrong.

$d='07-11-13';
echo $d;
echo strtotime($d);
echo "<br>";
echo strtotime("$d");

Isn't strtotime supposed to receive "YYYY-MM-DD"? like $d="2013-11-07"... — briosheje
– briosheje, Commented Nov 7, 2013 at 16:43
@briosheje strtotime can accept many different formats: php.net/manual/en/function.strtotime.php I believe you're on to the issue though, the function is confusing the month and day — Jeff Lambert
– Jeff Lambert, Commented Nov 7, 2013 at 16:44
strotime("2013-11-07") outputs 1383778800 which is correct. You should check php.net/manual/en/function.strtotime.php . Ps: strtotime("07-11-13") outputs 131194908400 to me, which is not correct, if I'm not going wrong :P — briosheje
– briosheje, Commented Nov 7, 2013 at 16:44
You need to put in 07-11-2013, that should give you the right time. It's getting confused because it can't work out what format you are using, whether you are using dd-mm-y or y-mm-dd. — Styphon
– Styphon, Commented Nov 7, 2013 at 16:50

briosheje · Accepted Answer · 2013-11-07 16:49:47Z

1

After a few checks, the error is actually NOT in the format you're passing, but rather on the way you're passing it.

What you should do is just replace "13" with "2013":

strtotime("07-11-2013");

output: 1383778800

echo strtotime("2013-11-07");

output: 1383778800

echo strtotime('07-11-13');

output: 1194908400

answered Nov 7, 2013 at 16:49

briosheje

7,4662 gold badges35 silver badges56 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Styphon · Accepted Answer · 2013-11-07 16:51:37Z

0

The problem is you need to specify a 4 digit year, so that strtime can fully work out which date format you are using. With 07-11-13 it probably thinks you are using 2007-11-13.

Change it to 07-11-2013 and you will get the correct answer.

answered Nov 7, 2013 at 16:51

Styphon

10.5k9 gold badges54 silver badges87 bronze badges

Comments

Zahidul Hossein Ripon · Accepted Answer · 2013-11-07 16:46:58Z

0

$d='07-11-13' is wrong, Try this

$d='2013-11-13';
echo $d;
echo strtotime($d);
echo "<br>";
echo strtotime("$d")

answered Nov 7, 2013 at 16:46

Zahidul Hossein Ripon

6726 silver badges17 bronze badges

Comments

AbraCadaver · Accepted Answer · 2013-11-07 16:48:23Z

0

strtotime() will accept:

m/d/y
d-m-y

With / it expects month/day and with - it expects day-month.

answered Nov 7, 2013 at 16:48

AbraCadaver

79.2k7 gold badges75 silver badges91 bronze badges

Collectives™ on Stack Overflow

strtotime conversion with variable error

4 Answers 4

Comments

Comments

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

4 Answers 4

Comments

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related