Remove element from array if string contains any of the characters

Question

Remove element from array if string contains any of the characters.For example Below is the actual array.

array(1390) {
  [0]=>
  string(9) "Rs.52.68""
  [1]=>
  string(20) ""php code generator""
  [2]=>
  string(9) ""Rs.1.29""
  [3]=>
  string(21) ""php codes for login""
  [4]=>
  string(10) ""Rs.70.23""

 }

I need the array to remove all the elements which start with RS.

Expected Result

 array(1390) {
      [0]=>
      string(20) ""php code generator""
      [1]=>
      string(21) ""php codes for login""


     }

What i tried so far :

foreach($arr as $ll)
{

if (strpos($ll,'RS.') !== false) {
    echo 'unwanted element';
}

From above code how can i remove unwanted elements from array .

$arr = array_filter($arr, function($value) { return strpos($value, 'Rs.') !== false; } — Mark Baker
– Mark Baker, Commented Nov 17, 2013 at 19:56

h2ooooooo · Accepted Answer · 2013-11-17 19:55:07Z

6

You can get the $key in the foreach loop and use unset() on your array:

foreach ($arr as $key => $ll) {
    if (strpos($ll,'RS.') !== false) {
        unset($arr[$key]);
    }
}

Note that this would remove none of your items as "RS" never appears. Only "Rs".

answered Nov 17, 2013 at 19:55

h2ooooooo

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Comments

GolezTrol · Accepted Answer · 2013-11-17 19:56:54Z

3

This sounds like a job for array_filter. It allows you to specify a callback function that can do any test you like. If the callback returns true, the value if returned in the resulting array. If it returns false, then the value is filtered out.

$arr = array_filter($arr, 
  function($item) { 
    return strpos($item, 'Rs.') === false; 
  });

answered Nov 17, 2013 at 19:56

GolezTrol

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Comments

Thomas C. · Accepted Answer · 2013-11-17 20:01:33Z

0

Rs is different than RS you want to use stripos rather than strpos for non case sensitive checking

foreach($arr as $key => $ll)
{    
  if (stripos($ll,'RS.') !== false) {
    unset($arr[$key]);
  }
}

or use arrayfilter as pointed out

edited Nov 17, 2013 at 20:01

answered Nov 17, 2013 at 19:55

Thomas C.

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