Remove element from array if contains some string/symbol

Question

I have an array containing some words and I want to remove the words that contain either a . (fullstop) or ; (semicolon) or some other symbols. I have read the solution on [ Remove item from array if item value contains searched string character ] but this doesn't seem to answer my problem.

What can I add to this code to remove also the words containing the other symbols other than semicolon?

function myFilter($string) {
  return strpos($string, ';') === false;
}

$newArray = array_filter($array, 'myFilter');

Thanks

Can we see the array your using.

Kitson88
– Kitson88

2017-01-09 22:09:49 +00:00
Commented Jan 9, 2017 at 22:09 — Kitson88
– Kitson88, Commented Jan 9, 2017 at 22:09

RomanPerekhrest · Accepted Answer · 2017-01-09 22:13:23Z

2

Use preg_match function:

function myFilter($string) {
    return !preg_match("/[,.]/", $string);
}

[,.] - character class which can be extended with any other symbols

answered Jan 9, 2017 at 22:13

RomanPerekhrest

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1 Comment

L.D Over a year ago

Nice and clean solution. Thanks

Jose Garrido · Accepted Answer · 2017-01-09 22:12:02Z

1

// $array is your initial array
$newArray = array();
foreach ($array as $item){
    if ((strpos($item, ';') > 0)||(strpos($item, '.') > 0))
        continue;
    $newArray[] = $item;
}

// Words with ; or . should be filtered out in newArray
print_r($newArray);

answered Jan 9, 2017 at 22:12

Jose Garrido

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