Display Json data using PHP

Question

I have a json file and I want to display its data in a PHP file. I use the below code but it gives me error.

$json = file_get_contents('data.json'); 
$data = json_decode($json);
foreach ($data as $value)
  {
  echo "$value[1]<br>";
  }

data.json file contains data in this format.

{
"users":[
{"id":"03B7F72C1A522631","user":"[email protected]"}, 
{"id":"27EB9CE8338083AE","user":"[email protected]"}, 
{"id":"E27854ABBFF8CD92","user":"[email protected]"}],
"status":
    {
    "version":"0.9.5.0",
    "command":"listusers",
    "opf":"json",
    "error":false,
    "code":0
    }
}

I want the Output as

User ID | User Email

03B7F72C1A522631 | [email protected]
27EB9CE8338083AE | [email protected]

json_decode($json, true); add second parameter if you want to use as array. — Mihai Iorga
– Mihai Iorga, Commented Nov 24, 2013 at 12:43
What do you mean by "it gives me error"? Is there any error message which you've forgot to share? — Nico Haase
– Nico Haase, Commented Apr 25, 2019 at 10:29

Patato · Accepted Answer · 2013-11-24 12:46:54Z

4

$json = file_get_contents('data.json'); 
$data = json_decode($json,true);
$users=$data['users'];
for($users as $user)
{
   echo $user['id']." ".$user['user'];
}
$status=$data['status'];

answered Nov 24, 2013 at 12:46

Patato

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Comments

Community · Accepted Answer · 2023-11-17 20:33:26Z

0

Use this which will give an associative array instead of an object

$data = json_decode($json,true);

for details have a look here json_decode function

edited Nov 17, 2023 at 20:33

CommunityBot

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answered Nov 24, 2013 at 12:43

Suvash sarker

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3 Comments

Arif Over a year ago

Now it gives this output "Array"

Suvash sarker Over a year ago

print_r($data) and see the full array

Arif Over a year ago

Thanks for your help, I update the question and I mentioned the desired output

akshay borase · Accepted Answer · 2019-04-25 10:16:18Z

0

get data from json file

$homepage = file_get_contents('url');

$someArray = json_decode($homepage, true);

foreach ($someArray as $key => $value) {
    echo "\nAddress: " . $value["address"] . "\n\n";
}

answered Apr 25, 2019 at 10:16

akshay borase

11 bronze badge

1 Comment

Nico Haase Over a year ago

Can you explain that further? What makes you think that your code solves the mysterious error?

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