error in shell scripting?

Question

I am trying a code in shell script. while I am trying to convert the code from batch script to shell script I am getting an error.

BATCH FILE CODE

:: Create a file with all latest snapshots
FOR /F "tokens=5" %%a in (' ec2-describe-snapshots ^|find "SNAPSHOT" ^|sort /+64') do set "var=%%a" 
set "latestdate=%var:~0,10%" 
call ec2-describe-snapshots |find "SNAPSHOT"|sort /+64 |find "%latestdate%">"%EC2_HOME%\Working\SnapshotsLatest_%date-today%.txt"

CODE IN SHELL SCRIPT

#Create a file with all latest snapshots
FOR snapshot_date in $(' ec2-describe-snapshots | grep -i "SNAPSHOT" |sort /+64') do set "var=$snapshot_date" 
set "latestdate=$var:~0,10" 
ec2-describe-snapshots |grep -i "SNAPSHOT" |sort /+64 | grep "$latestdate">"$EC2_HOME%/SnapshotsLatest_$today_date"

I want to sort the snapshots according to dates and to save the snapshots that are created in latest date in a file.

SAMPLE OUTPUT OF ece-describe-snapshots:

`SNAPSHOT        snap-5e20   vol-f660    completed       2013-12-10T08:00:30+0000        100%    109030037527    10      2013-12-10: Daily Backup for i-2111 (VolID:vol-f9a0 InstID:i-2601)`

It will contain records like this

the snaphsot latest file should cointain:

SNAPSHOT    snap-cdd617f3   vol-f66409a0    completed   2013-12-04T09:24:50+0000    100%    109030037527    10  2013-12-04: Daily Backup for Sanjay_Test_Machine (VolID:vol-f66409a0 InstID:i-26048111)
SNAPSHOT    snap-c7d617f9   vol-3d335f6b    completed   2013-12-04T09:24:54+0000    100%    109030037527    10  2013-12-04: Daily Backup for sachin_test_VPC (VolID:vol-3d335f6b InstID:i-e1c443d6)

Any suggestion or lead is appreciated.

What error are you getting? Shell is case sensitive, use for instead of FOR. — choroba
– choroba, Commented Dec 10, 2013 at 8:39
Describe what you want to do and provide input data and desired output. — Édouard Lopez
– Édouard Lopez, Commented Dec 10, 2013 at 9:01
i have some snapshots made on amazon, i want to find the latest snapshots made on a date and then want to store them in a file. like date 2013-12-10 snapshots made on this date should be stored in file. Contents of snapshotslatest file should be SNAPSHOT snap-c17f3 vol-f69a0 completed 2013-12-04T09:24:50+0000 100% 109030037527 10 2013-12-04: Daily Backup for Sanjay_Test_Machine (VolID:vol-f66409a0 InstID:i-26048111) SNAPSHOT snap-c7d617f9 vol-3d335f6b completed 2013-12-04T09:24:54+0000 100% 109030037527 10 2013-12-04: Daily Backup for sacht_VPC (VolID:vol-3db InstID:i-ed6) — user3086014
– user3086014, Commented Dec 10, 2013 at 9:23
@user3086014, please put your sample input and output up in the question where it can be formatted properly. In particular, please show the output of ec2-describe-snapshots — glenn jackman
– glenn jackman, Commented Dec 10, 2013 at 21:58
@glennjackman: i have added the sample output of ec2-describe-snapshots in the question itself — user3086014
– user3086014, Commented Dec 11, 2013 at 4:44

glenn jackman · Accepted Answer · 2013-12-11 12:21:16Z

1

Its a code smell that you have to run the command twice.

It was unclear that you wanted just the lines for the most recent day. Try this:

ec2-describe-snapshots | sort -rk 5 | awk '
    $1 != "SNAPSHOT" {next}
    NR == 1 { split($5, a /T/); date = a[1]; }
    $5 ~ date {print}
' > "$EC2_HOME/SnapshotsLatest_$today_date"

If you only want today's snapshots, even easier

today=$(date +%F)
ec2-describe-snapshots | sort -rk 5 | awk -v date=$today '
    $1 == "SNAPSHOT" && $5 ~ date {print}
' > "$EC2_HOME/SnapshotsLatest_$today"

answered Dec 11, 2013 at 12:21

glenn jackman

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