Javascript function stringing

Question

Could anyone explain to me why the third alert function is simply not called?, and a possible reading resource in relation to the error.

<script type="text/javascript">

$( document ).ready(function() {
   myFunction();
});

function myFunction()
{
    alert("First Function");

    mySecondFunction(function () {
        alert("Third Function");
    });
}

function mySecondFunction()
{
    alert("Second Function");
}

@SantoshJoshi he's passing a parameter, a function. He's just not executing it. — DontVoteMeDown
– DontVoteMeDown, Commented Dec 13, 2013 at 17:27
FYI $( document ).ready(function() { myFunction(); }); in your case could be wrote $(myFunction) — A. Wolff
– A. Wolff, Commented Dec 13, 2013 at 17:28
@DontVoteMeDown, my bad, i mean to say he has not declared function to take any paramaters, — Santosh Joshi
– Santosh Joshi, Commented Dec 13, 2013 at 17:30

DontVoteMeDown · Accepted Answer · 2013-12-13 17:25:28Z

8

Because you're doing nothing with that function in the parameter. You can do this:

function mySecondFunction(func)
{
    alert("Second Function");
    func();
}

answered Dec 13, 2013 at 17:25

DontVoteMeDown

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Comments

Martin Majer · Accepted Answer · 2013-12-13 17:27:30Z

3

You are passing anonymous function function () { alert("Third Function"); } as a parameter to mySecondFunction(), but you're not calling this anonymous function anywhere inside mySecondFunction().

This would work:

function mySecondFunction(callback)
{
    alert("Second Function");
    callback();
}

answered Dec 13, 2013 at 17:27

Martin Majer

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1 Comment

garyamorris Over a year ago

Thanks for the help, you were spot on.

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